Assuming that you got the numbers right and that I did my calculations right, then the answer is <span>2998.45 tons.</span>
Answer:
200.
Step-by-step explanation:
0-49=round down 50-99=round up.
Answer:
The inference that can be made using the dot plot is:
The range of round 1 is greater than the round 2 range.
Step-by-step explanation:
<u>Round 1:</u>
Score Frequency
1 0
2 2
3 3
4 2
5 1
Hence, the minimum score of Round 1 is: 2
maximum score is: 5
Hence, Range=Maximum value-Minimum score
=5-2
=3
Similarly, <u>Round-2</u>
Score Frequency
1 0
2 0
3 0
4 4
5 4
Hence, the minimum score of Round 1 is: 4
maximum score is: 5
Hence, Range=Maximum value-Minimum score
=5-4
=1
The scores of round 2 are higher than round-1.
Since round 2 have a higher frequency for higher scores as compared to round-1.
Hence, Range of round 1 is greater than the range of Round-2.
Compute the medium . 7, 2, 8, 5, 10, 7, 9, 10, 2, 5, 8, and 6.
enot [183]
Median:7
i hope this helps!
Answer:
a) 26 tickets
b) £5
c) chips, pastie and a soft drink
Step-by-step explanation:
Given:
- Price of one ticket = £7.50
- Total available to spend = £200
<u>Part (a)</u>
Greatest number of tickets = total available to spend ÷ cost of one ticket
= 200 ÷ 7.5
= 26.66666...
= 26 tickets
(We can't round up, as 27 tickets would cost £202.50)
<u>Part (b)</u>
Money left = Total available spend - cost of 26 tickets
= 200 - (26 × 7.50)
= 200 - 195
= £5
<u>Part (c)</u>
Cost of 3 items = £10 - change
= £10 - £4.70
= £5.30
One of the items can't be a burger, as £5.30 - £3.50 = £1.80
and £1.80 is not enough to buy 2 items.
If he buys chips, he has: £5.30 - £2.40 = £2.90 left to spend on the other 2 items.
Pastie + Soft Drink = £1.60 + £1.30 = £2.90
So he can buy: chips, pastie and a soft drink