H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t
h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79
g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8
Between 2 and 3 seconds.
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1
h(t) = g(t) ⇒ 131 = 131
It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up.
Answer:
Step-by-step explanation:
x = first number, y = second number
4x - 3y = 12
2x + 3y = 6
------------------add
6x = 18
x = 18/6
x = 3
4x - 3y = 12
4(3) - 3y = 12
12 - 3y = 12
-3y = 12 - 12
-3y = 0
y = 0
solution : (3,0)
8+6=14 and 14-8=6 so the 2 numbers are 8 and 6
Answer:
No
Step-by-step explanation:
You only pay the $4.50 once.
Answer:
1/4
i hope this is the answer you are looking for
Step-by-step explanation:
