(0,0) and (6,0)
First we subtract 18x from both sides
3x²-18x=0
Factor out a 3x
3x(x-6)=0
This means that x is either 0 or 6
Domain: (-∞,∞)
Range: (3,∞)
x-intercepts: none
y-intercepts: (0,7)
Interval positive: (3,∞)
Interval negative: none
Interval increasing: (7,∞)
Interval decreasing: (-∞,7)
I'm not sure what the average rate of change over is though.
The area of the square is 100ft
Answer:
4/25
Step-by-step explanation:
i am pretty sure this is correct:)
Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
_____
<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
