Let the distance traveled by car X be x km
<span>let the distance traveled by car Y by y km </span>
<span>their paths form a right-angled triangle. </span>
<span>Let the distance between them be D km </span>
<span>D^2 = x^2 + y^2 </span>
<span>2D dD/dt = 2x dx/dt + 2y dy/dt </span>
<span>dD/dt = (x dx/dt + y dy/dt)/D </span>
<span>at the given case: </span>
<span>x = 60, y = 80 , dx/dt = 80, dy/dt = 100 </span>
<span>D^2 = 60^2 + 80^2 = 10000 </span>
<span>D = 100 </span>
<span>dD/dt = (60(80) + 80(100))/100 </span>
<span>= 128 </span>
(0 , 3) is the ordered pair
Answer:
I think Mikhail's age is 5
The question say Gabrielle's age is 3 times his
so 5 × 3 = 15
15 + 5 = 20
5x=38-3
5x=35
x=7 good luck
If you have an eye for geometry you can see that each shape has the dimensions x by 3x.
Thus, (3 blocks)(3x per block) comes out to 9x=16.2 cm = length of rectangle.
If this is true, then x = 1.8 cm
Then the area of the rect. is (width)(length) = (9 cm)(16.2 cm) = 145.8 cm^2.
Algebraically, 5(1.8 cm)(16.2 cm) = 145.8 cm^2 (answer)