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Gala2k [10]
3 years ago
14

4. The medium ground finch and the cactus finch are adapted to consume different types of foods. Can you think of a situation in

which the medium ground finches would have a survival advantage over the cactus finches? A disadvantage?
Biology
2 answers:
Sedaia [141]3 years ago
4 0

Answer:

Long beaks of medium ground finches allows them to opt for alternate sources of food in times of extremities while this is not the case with the cactus finches.

Explanation:

The medium ground finches have larger beaks and thus apart from small seeds they can also break open the large seed. In case if the small seeds get scarce, a medium ground finch can still survive by taking advantage of feeding on alternate source of food but small beaked birds such as cactus finches shall die out of starvation.

This adaptation of medium ground finches gives it a survival advantage over the cactus finches

Korvikt [17]3 years ago
3 0

Answer:

Large beak size of medium ground finch assists in aiding advantage to survival and reproduction as compared to cactus finch.

Explanation:

The medium ground finch will take the advantage of its peak size and structure over the cactus finch for both its survival and reproduction.  

Unlike the cactus finch, the medium finch have large beaks due to which they take advantage of alternate food sources such as large seeds, hard seeds etc.  

Beak size also plays an essential role in attracting males with large beak size and hence  medium ground finch reproduce easily and frequently as compared to cactus finch

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During a lunar eclipse, what blocks the light from hitting the moon's surface?
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3 years ago
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Gold has a specific heat of 0.129 J/(g×°C). How many joules of heat energy are required to raise the temperature of 15 grams of
Elodia [21]

Answer:

\boxed {\boxed {\sf 121.905 \ J  }}

Explanation:

We are asked to find the energy given mass, specific heat, and change in temperature. Therefore, we must use this formula;

q= mc \Delta T

The mass is 15 grams and the specific heat is 0.129 J/(g×°C). Let's calculate the change in temperature.

  • ΔT= final temperature - initial temperature
  • ΔT= 85 °C- 22°C = 63°C

Now we know all the values:

m= 15 \ g \ \\c= 0.129 \ J / (g* \textdegree C) \\\Delta T= 63 \ \textdegree C

Substitue the values into the formula.

q= (15 \ g)( 0.129 \ J / (g* \textdegree C)) ( 63 \ \textdegree C)

Multiply the first numbers together. The grams will cancel.

q= (1.935 \ J/ \textdegree C) ( 63 \ \textdegree C)

Multiply again, this time the degrees Celsius cancels.

q= 121.905 \ J

<u>121.905 Joules</u> are required.

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2 years ago
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