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Lubov Fominskaja [6]
3 years ago
12

Which ratio is not equivalent to the other three 2/3 12/15 6/9 or 18/37

Mathematics
1 answer:
Kryger [21]3 years ago
6 0
Last one because it should be 18:36 -JZ
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A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

8 0
4 years ago
Pls help i don't get this
abruzzese [7]

Answer:

10 meters

Step-by-step explanation:

C = D/N

Circumference = Distance / Number of Rotations

8 0
2 years ago
Read 2 more answers
an item is regularly priced at $90 . alan bought it on sale for 30% off the regular price. how much did alan pay?
Minchanka [31]

Answer:

$63

Step-by-step explanation:

100-30=70%

0.7*90=63

3 0
3 years ago
What are the solutions to x2 + 8x + 7 = 0?
nikitadnepr [17]

Answer:

x= -1 and x= -7

hope it helps.

5 0
3 years ago
Enter the decimal equivalent of 9/4.
Finger [1]

Answer:

2.25

Step-by-step explanation:

\frac{9}{4} = 2\frac{1}{4} = 2.25.

4 0
3 years ago
Read 2 more answers
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