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Lubov Fominskaja [6]
3 years ago
12

Which ratio is not equivalent to the other three 2/3 12/15 6/9 or 18/37

Mathematics
1 answer:
Kryger [21]3 years ago
6 0
Last one because it should be 18:36 -JZ
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Please answer the question now in two minutes
oksian1 [2.3K]

Answer:

Coordinates of point P is (-14,3).

Step-by-step explanation:

Given that mid point of line segment \overline {PQ} is at <em>M(-9, 8.5).</em>

Q is at <em>(-4, 14)</em>.

Let coordinate of P be (x,y).

Using the ratio, we can say the following:

<em>The coordinates of mid point</em> (X,Y) of a line with endpoints (x_1, y_1) and (x_2, y_2) is given as:

X=\dfrac{(x_1+ x_2)}{2}

Y=\dfrac{(y_1+ y_2)}{2}

Using the formula for above given dimensions:

-9 =\dfrac{x+(-4)}{2}\\\Rightarrow x = -18+4 = -14

8.5=\dfrac{(14+ y)}{2}\\\Rightarrow y = 17-14 =3

So, the <em>coordinates of point P are</em> (-14,3).

6 0
3 years ago
Me pueden ayudar profabor ​
Svet_ta [14]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
I dont know!!!!!!!!!!!!!!!!!!!!!!!
djyliett [7]

Answer:

9in2

Step-by-step explanation:

the 2 is an expononent.

3 0
3 years ago
A line that includes the point (-4, 7) has a slope of 6. What is its equation in point-slope
aalyn [17]
Point slope formula: y-y1=m(x-x1). Answer: y-7=6(x-(-4))
7 0
3 years ago
he owner of a local supermarket wants to estimate the difference between the average number of gallons of milk sold per day on w
stellarik [79]

Answer:

90% confidence interval is ( -149.114, -62.666   )

Step-by-step explanation:

Given the data in the question;

Sample 1                                Sample 2

x"₁ = 259.23                            x"₂ = 365.12

s₁  = 34.713                              s₂ = 48.297

n₁ = 5                                       n₂ = 10

With 90% confidence interval for μ₁ - μ₂ { using equal variance assumption }

significance level ∝ = 1 - 90% = 1 - 0.90 = 0.1

Since we are to assume that variance are equal and they are know, we will use pooled variance;

Degree of freedom DF = n₁ + n₂ - 2 = 5 + 10 - 2 = 13

Now, pooled estimate of variance will be;

S_p^2 = [ ( n₁ - 1 )s₁² + ( n₂ - 1)s₂² ] / [ ( n₁ - 1 ) + ( n₂ - 1 ) ]

we substitute

S_p^2 = [ ( 5 - 1 )(34.713)² + ( 10 - 1)(48.297)² ] / [ ( 5 - 1 ) + ( 10 - 1 ) ]

S_p^2 = [ ( 4 × 1204.9923) + ( 9 × 2332.6 ) ] / [  4 + 9 ]

S_p^2 = [ 4819.9692 + 20993.4 ] / [  13 ]

S_p^2 = 25813.3692 / 13

S_p^2 = 1985.64378

Now the Standard Error will be;

S_{x1-x2 = √[ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

S_{x1-x2 = √[ ( 1985.64378 / 5 ) + ( 1985.64378 / 10 ) ]

S_{x1-x2 = √[ 397.128756 + 198.564378 ]

S_{x1-x2 = √595.693134

S_{x1-x2 = 24.4068

Critical Value = t_{\frac{\alpha }{2}, df = t_{0.05, df=13 = 1.771  { t-table }

So,

Margin of Error E =  t_{\frac{\alpha }{2}, df × [ ( S_p^2 / n₁ ) + ( S_p^2 / n₂ ) ]

we substitute

Margin of Error E = 1.771 × 24.4068

Margin of Error E = 43.224

Point Estimate = x₁ - x₂ = 259.23 - 365.12 = -105.89

So, Limits of 90% CI will be; x₁ - x₂ ± E

Lower Limit = x₁ - x₂ - E = -105.89 - 43.224 = -149.114

Upper Limit = x₁ - x₂ - E = -105.89 + 43.224 = -62.666

Therefore, 90% confidence interval is ( -149.114, -62.666   )

3 0
3 years ago
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