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Lubov Fominskaja [6]
3 years ago
12

Which ratio is not equivalent to the other three 2/3 12/15 6/9 or 18/37

Mathematics
1 answer:
Kryger [21]3 years ago
6 0
Last one because it should be 18:36 -JZ
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When h has the value of 4 calculate 5h-3
Margaret [11]
5h - 3 = 17

First, substitute h for 4 and the equation becomes 5(4)-3
Then, use PEMDAS (order of operations) to answer.
5 x 4 = 20
20 - 3 = 17
6 0
3 years ago
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Petrina had a piece of red ribbon that measured 2.4 m long. she also had a piece of blue ribbon which was 7 8 m long. what was t
katen-ka-za [31]

The total length of red and blue ribbons is 10.2 m.

Given that, the length of the red ribbon =2.4 m and the length of the blue ribbon =7.8 m.

<h3>How to add two decimals?</h3>

Adding decimals is similar to the usual addition of whole numbers. We know that a decimal number is a number with a whole number part and a fractional part which is separated by a decimal point.

Now, the length of the red ribbon + the length of the blue ribbon=2.4+7.8

=10.2 m

Therefore, the total length of red and blue ribbons is 10.2 m.

To learn more about the addition of decimals visit:

brainly.com/question/17612968.

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7 0
2 years ago
Can someone solve this?
ladessa [460]
  • First question:

Recall that \cos^2x+\sin^2x=1 and \sqrt{x^2}=|x| for all x. So

\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|

\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|

For 0, we expect both \cos x>0 and \sin x>0 (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, |x|=x if x>0.

So we have

\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}

making H the answer.

  • Second question:

C is always true, because the inequality reduces to x > y.

6 0
3 years ago
X+y=5 3x+3y=10 eliminacion
Dominik [7]



[1] y = -x + 5



3x + 3•(-x +5) = 10

0 = -5 => NO solution
8 0
3 years ago
What is 3/5 + 1/2? As in fractions, I can’t figure it out!! :(
ella [17]

Step-by-step explanation:

\frac{3}{5}  +  \frac{1}{2}  \\  \\  =  \frac{3 \times 2 + 1 \times 5}{5 \times 2}  \\  \\  =  \frac{6 + 5}{10}  \\  \\  =  \frac{11}{10}  \\  \\  = 1 \frac{1}{10}

5 0
3 years ago
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