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Inga [223]
3 years ago
13

A car traveling at 45 m/s starts to decelerate steadily. It comes to a complete stop in 10 seconds. What is it’s acceleration

Physics
1 answer:
VARVARA [1.3K]3 years ago
5 0

a=(Vf-Vi)/t = [(0 m/s)-(45m/s)/(10s)=-45/10m/s^2= -4.5m/s^2

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If distance between two charges increased by 2 times then force
kati45 [8]

Explanation:

The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.

5 0
3 years ago
A horizontal force of 92.7 N is applied to a 40.5 kg crate on a rough, level surface. If the crate accelerates at 1.13 m/s2, wha
lord [1]

Answer:

The value is F_f =  46.935 \  N

Explanation:

From the question we are told that

    The  magnitude of the horizontal force is F  =  92.7 \  N

     The mass of the crate is  m  =  40.5 \  kg

     The acceleration of the crate is  a =  1.13 \ m/s

Generally the net force acting on the crate is mathematically represented as

       F_{net} =  F -  F_f =  ma

Here F_f is force of kinetic friction (in N) acting on the crate

      So  

            92.7  -  F_f =  40.5 * 1.13

=>         F_f =  46.935 \  N

5 0
3 years ago
Please help!!!! 70 points, i really need this! D:
jolli1 [7]

1. Frequency 2. measure from trough to trough

7 0
3 years ago
Read 2 more answers
The 2.5-Mg van is traveling with a speed of 100 km>h when the brakes are applied and all four wheels lock. If the speed decre
Andrew [12]

Answer:

0.34

Explanation:

2.5 Mg = 2500 kg

The change in speed from 100 km/h to 40 km/h is

\Delta v = 100 - 40 = 60 km/h = 60 * 1000 / (60 * 60) = 16.67 m/s

The deceleration caused by friction force is the change in speed per unit of time

a = \Delta v / \Delta t = 16.67 / 5 = 3.33 m/s^2

Using Newton 2nd law we can calculate the friction force that caused this deceleration:

F = ma = 2500 * 3.33 = 8333 N

Let g = 9.8m/s2. Friction force is the product of normal (gravity) force and friction coefficient

F = mg\mu

8333 = 2500*9.8\mu

\mu = \frac{8333}{2500 * 9.8} = 0.34

4 0
3 years ago
Pleaseee helpppp meeeeeee I will give pountsss
MrRa [10]

Answer:

<h3>8. </h3>

m= 0. 113 kg

W = 1.1074 N

g = 9.8 m/ s²

<h3>9. </h3>

m= 870 kg

W = 8526 N

g = 9.8 m/s²

<h3>10.</h3>

a) weight on earth:

weight = mass × acceleration due to gravity (g)

<em>g</em><em> </em><em>on</em><em> </em><em>earth</em><em> </em><em>=</em><em> </em><em>9</em><em>.</em><em>8</em><em> </em><em>m</em><em>/</em><em>s</em><em>²</em>

W = 75 × 9.8

<u>W</u><u> </u><u>= </u><u>7</u><u>3</u><u>5</u><u> </u><u>N</u>

b) g on Mars

285 = 75 × g

g = 285/ 75

<u>g = 3.8 m/ s²</u>

3 0
3 years ago
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