Question

A particle is moving along a straight line such that its' acceleration is defined as

Answer 1

Answer:

1. $s=-vt^2$

2. $v=\frac{s}{t}$

3. $a=-2\times \frac{s}{t}$

Explanation:

Given:

Acceleration as a Function of velocity, $a=-2v\ m.s^{-2}$

Velocity, $v=20\ m.s^{-1}$ at displacement s=0 and t=0

1.

Particles position as a function of time:

Using equation of motion:

$s=u.t+\frac{1}{2} a.t^2$

where:

$u =$ initial velocity

$v=$ final velocity

so,

$s=0+\frac{1}{2}\times (-2v) t^2$

$s=-vt^2$

2.

Particle velocity as a function of time:

$v=\frac{s}{t}$

3.

Particles acceleration as a function of time:

$a=-2\times \frac{s}{t}$