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dimulka [17.4K]
2 years ago
14

A building code allows a maximum of 140 people in a meeting room. There is one large table in the room, along with some small ta

bles. When filed, the large table seats 15 people, and the small table each seat 5 people. Which of the following can be used to find t, the greatest number of small tables that can be filled when the large tables are also filled?
Mathematics
2 answers:
lara [203]2 years ago
7 0

Answer:

25 tables

Step-by-step explanation:

140-15=125

after the big table is filled 125 people are left

small tables fit 5 people

125÷5=25

1 big table and 25 small tables are needed to seat everyone

Alina [70]2 years ago
7 0
…..25 tables!!!…






…….hope ……this helps you! …..
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Simplify.<br><br>(7y)^2<br><br>Write your answer without parentheses.
kiruha [24]

Answer:

Step-by-step explanation:

(7y)² = 7²×y² = 49y²

4 0
3 years ago
a fishbowl shaped like a sphere is filled with water. The fishbowl has a diameter of 16 inches. Which measurement is closest to
gregori [183]

Answer:

The volume of the water in the fishbowl is equal to

(682\frac{2}{3})\pi\ in^{3}  or  2,144.6\ in^{3}

Step-by-step explanation:

we know that

The volume of the sphere (a fishbowl) is equal to

V=\frac{4}{3}\pi r^{3}

In this problem we have

r=16/2=8\ in ----> the radius is half the diameter

substitute

V=\frac{4}{3}\pi (8^{3})=\frac{2,048}{3}\pi\ in^{3}

convert to mixed number

\frac{2,048}{3}\pi\ in^{3}=\pi (\frac{2,046}{3}+\frac{2}{3})=(682\frac{2}{3})\pi\ in^{3}

(3.14156)*(682\frac{2}{3})=2,144.6\ in^{3}

6 0
3 years ago
Read 2 more answers
Cw 10.5 10.5 V. W<br> A great
Semmy [17]

Answer:

Refer to step-by-step.

Step-by-step explanation:

12.  x = 28

BC = x

AB = 96

AC = 100

We use the Pythagorean theorem to find the value of x.

a² + b² = c²

x² + 96² = 100²

x² + 9216 = 10000

x² = 10000-9216

x² = 784

√x² = √784

x = 28

13. x = 64

a² + b² = c²

48² + x² = 80²

2304 + x² = 6400

x² = 6400 - 2304

x² = 4096

√x² = √4096

x = 64

14. YES and 25 = 25

a² + b² = c²

3² + 4² = 5²

9 + 16 = 25

25 = 25

So this means that AB is tangent to the circle.

15. NO and 45 ≠ 49

a² + b² = c²

3² + 6² = 7²

9 + 36 = 49

45 = 49

So this means the AB is not tangent to the circle.

16. x = 4.5 and P = 52

To find the value of x, we need to determine the value of our hypotenuse.

QU is congruent to QT, therefore, QT = 4

UR is congruent with SR, therefore, UR = 13

PS is congruent to AB, therefore:

2x = 9

Divide both sides by 2

x = 4.5

The perimeter of a triangle is:

P = a + b + c

a = 9 + 4 or 13

b = 2(4.5) + 13 or 22

c = 4 + 13 or 17

P = 13 + 22 + 17

P = 52

17. x = 13 and P = 72

TJ is congruent to UJ, therefore, TJ = 13

x = 13

The perimeter of a parallelogram is:

P = 2(a+b)

a = HR + RK

b = KU + UJ

a = 13 + 5 or 18

b = 5 + 13 or 18

P = 2(18 + 18)

P = 2(36)

P = 72

18. x = 8 and P = 80

We know that part of the whole of 26 is 18 because one side is congruent to 18.

to find the value of the other half, we simply subtract 18 from 26.

26 - 18 = 8

x is congruent to 8, therefore x = 8

The line segment 14 is congruent to the opposite segment of x, therefore making the value 14.

So then we have:

a = 8 + 14 or 22

b = 26

c = 18 + 14 or 32

P = a + b + c

P = 22 + 26 + 32

P = 80

19. x = 6 and P = 52

Now we have the case of x + 2 is congruent to 8.

x + 2 = 8

Combine like terms.

x = 8 - 2

x = 6

Now that we have the value of x, we can simply look for the value of the line segment attached to it.

4 is congruent to the line segment attached to x + 2, therefore the value is 4.

To find the perimeter we have to add all sides together.

P = (8+5)+(5+9)+(9+4)+(8+4)

P = 52

20. x = 5, y = 2, z =10, and P = 68

Let's take this one step at a time.

First we look for x.

2x + 2 = 3x - 3

Combine like terms.

2x - 3x = -3 - 2

-x = -5

Divide both sides by -1.

x = 5

Now let's get the value of y.

5y - 2 = 3y + 2

Combine like terms.

5y - 3y = 2 + 2

2y = 4

Divide both sides by 2.

y = 2

Now let's look for z.

34 - 2z = z + 4

Combine like terms.

-2z - z = 4 - 34

-3z = -30

Divide both sides by -3.

z = 10

Now that we have the values of x, y, and z. We can substitute them to find the values of our segments.

2x + 2

2(5) + 2 = 12

3x - 3

3(5)-3 = 12

5y - 2

5(2) - 2 = 8

3y + 2

3(2) + 2 = 8

z + 4

10 + 4 = 14

34 - 2z

34 - 2(10)

34 - 20 = 14

Now that we have our values let's look for our perimeter.

P = a + b + c

P = (12 + 8) + (12 + 14) + (14 + 8)

P = 20 + 26 + 22

P = 68

4 0
3 years ago
The figure below shows three uniform objects: a rod with m1 = 7.00 kg, a right triangle with m2 = 3.70 kg, and a square with m3
navik [9.2K]
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G= m1x5 + m2 x 4sqrt (2) + m3x 3sqrt (2)  / 16  =  35 +4 x 3.7x sqrt (2) + 5.3 x3 4sqrt (2) / 16 =35 + 36<span> sqrt (2) / 16
G = 53.09
LOOK AT THE IMAGE

</span>

6 0
2 years ago
A roadside vegetable stand sells pumpkins for $5 each and tomatoes for $3 each. The total sales on a certain day was $98. If the
dexar [7]

Answer:

16 tomatoes

Step-by-step explanation:

50+3t=98

3t=48

t=16

8 0
3 years ago
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