X+y+z=11, x-y+z=5, x-z=y+1 and solve it by any of the methods: isolation, elimination or determinants. isolation (or back substitution, would be for instance: z = 11-x-y, z=5-x+y, z = x-y-1 and then impose z=z:
11-x-y=5-x+y,
11-x-y=x-y-1,
The first takes you to: 6=2y or y=3, then the second to 12=2x or x=6, so that:
x=6, y=3, z=2.
You can see that it checks out
Answer:
36V²+84V+49
Step-by-step explanation:
since it is (7+6V) in two places,therefore
7(7+6v)+6v(7+6v)
49+42v+42v+36v²
36v²+84v+49
Corresponding sides are in the same ratio, therfore
12/x = 6/ 8
6x = 96
x = 16
<span>The equation of a circle is (x-a)</span>²+(y-b)²=R²
(x-4)²+(y-0)²=(2√3)²
(x-4)²+y²=12