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Semenov [28]
3 years ago
10

ASAP PLEASE HELP!! “Find the quotient”

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
4 0

Answer:

The quotient is \frac{x(2x-3)}{7} answer (D)

Step-by-step explanation:

\frac{2x-3}{x} ÷ \frac{7}{x^{2} }

In division with fractions we reverse the fraction after division sign and change division sign to multiplication sine

\frac{2x-3}{x} × \frac{x^{2} }{7}

\frac{2x-3}{1} × \frac{x}{7}

\frac{x(2x-3)}{7}

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A train travels 210.6 miles in 1.3 hours what is the trains average speed?
grin007 [14]
Average speed = total distance/ total time
210.6/1.3= 162
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3 years ago
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If x^2-x-6 and x^2+3x-18 hacpve a common factor (x-a) then find the value of a.​
DedPeter [7]

Answer:

a = 3

Step-by-step explanation:

Factor both expressions

x² - x - 6

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (- 1)

The factors are - 3 and + 2 , since

- 3 × 2 = - 6 and - 3 + 2 = - 1 , thus

x² - x - 6 = (x - 3)(x + 2)

-----------------------------------

x² + 3x - 18

consider factors of constant term (- 18) which sum to give the coefficient of the x- term (+ 3)

The factors are + 6 and - 3 , since

6 × - 3 = - 18 and 6 - 3 = + 3 , thus

x² + 3x - 18 = (x + 6)(x - 3)

Both expressions have a common factor of (x - 3)

Compare with (x - a ), then a = 3

3 0
3 years ago
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50 points For these answers
Y_Kistochka [10]
Answer = 16 square blocks.

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Sabendo que "K" satisfaz a equação {2(k-8) + 3(-k+1) = -4k +11} Os valores reais de x que satisfazem a equação 15x² - kx + 1 = 0
erastova [34]

Answer:

D) 1/5 e 1/3

Step-by-step explanation:

You have the following quadratic equation:

15x^2-kx+1=0           (1)

In order to find the values of x that are solution to the equation (1), you first find the solution for k in the following equation:

2(k-8)+3(-k+1)=-4k+11\\\\2k-16-3k+3=-4k+11\\\\2k-3k+4k=11+16-3\\\\3k=24\\\\k=8

Next, you replace the previous value of k in the equation (1) and you use the quadratic formula to find the roots:

15x^2-8x+1=0\\\\x_{1,2}=\frac{-(-8)\pm \sqrt{(-8)^2-4(15)(1)}}{2(15)}\\\\x_{1,2}=\frac{8\pm 2}{30}\\\\x_1=\frac{1}{5}\\\\x_2=\frac{1}{3}

Then, the roots of the equation (1) are

D) 1/5 e 1/3

5 0
3 years ago
Solve the literal equation for the given variable.<br> n = 4/5(m+7);m
dem82 [27]

Answer:

m = (5n/4) -7

Step-by-step explanation:

n = 4/5(m + 7);m\\(5)n = 4(m + 7)\\5n/4 = m + 7\\m = (5n/4)/7

7 0
3 years ago
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