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Pepsi [2]
3 years ago
6

Please help

Mathematics
1 answer:
Nikitich [7]3 years ago
5 0
10q-3r=14, 10q=3r-14 10q=3r/10+14/10

q=3/10r+7/5
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A recent taste test showed that 85% of people liked a new chicken sandwich recently added to a restaurant’s menu. The restaurant
Vesna [10]

Answer:

a) The margin of error = 0.11

b) The interval estimate = (0.74, 0.96)

c) Not valid because 68% = 0.68 is less than the values in the interval estimate

Step-by-step explanation:

The statistical data from the population and the simulation are;

The percentage of the people that liked the new chicken sandwich = 85% = The population proportion

The percentage the restaurant manager claims liked the new sandwich = 68%

The number of trials of the simulation = 100 trials

The sample size of each trial = 30

The point estimate of each trial = 0.85

The minimum sample proportion = 0.66

The maximum sample proportion = 0.88

a) The confidence interval = (0.66, 0.88)

By the half the range method, the margin of error is given by half the width of the confidence interval

∴ The margin of error, MOE = (0.88 - 0.66)/2 = 0.11

b) The interval estimate are the expected range of numbers for a parameters

The interval estimate = The point estimate ± MOE

∴ The interval estimate = 0.85 ± 0.11 = (0.74, 0.96)

Given that the manager's claim of 68% is not within the interval estimate, the manager's claim is not valid based on the expected values for the people that liked the new sandwich found with the point estimate and the margin of error

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