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3 years ago

Please help

Mathematics

1 answer:

Nikitich [7]3 years ago

5 0

10q-3r=14, 10q=3r-14 10q=3r/10+14/10

q=3/10r+7/5

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30 POINTS, please help me!

k0ka [10]

Number 9 is A number 10 is C and number 11 is B thank you for your time

4 0

3 years ago

Find the equation of the line that passes thru (-1,-5) and is parallel to 3x+y=-5. Show work.

sertanlavr [38]

Answer:

$y=-3x-8$

Step-by-step explanation:

slope-intercept form:

$y=mx+b$

Start with the given equation, and to find the slope, convert it to slope-intercept form by solving for y.

$3x+y=-5$

In this case, all you need to do is subtract 3x from both sides.

$y=-3x-5$

Here, the slope is -3. The slope of a parallel line will also be -3.

Now, we have 3 known variables. We have the slope and the x and y of a known point. Use those 3 knowns to solve for the 1 unknown, the y-intercept.

$y=mx+b\\-5=(-3)(-1)+b\\-5=3+b\\-8=b\\b=-8$

Finally, with the slope and the y-intercept, you can write the equation of the line:

$y=-3x-8$

3 0

3 years ago

At a manufacturing plant where switches are made, it is a known fact that 2% of all switches are defective. If two switches are

olchik [2.2K]

Answer:

The probability that exactly one switch is good is

$P(x) =0.0392$

Step-by-step explanation:

The probability that a switch is defective is:

$P(D) = \frac{2}{100} =0.02$

The probability that a switch is not defective is

$P(D') = 1-P(D)=0.98$

Therefore, if two switches are selected, the probability that exactly 1 is good is:

$P(1=1)=P (D) P (D ') + P (D') P (D)$

$P(x)=(0.02)(0.98) + (0.98)(0.02)$

$P(x) =0.0392$

6 0

3 years ago

Read 2 more answers

Which expression represents the<br>statement "the product of 3 less than a<br>number and 5"}

yan [13]

Answer:

5(x-3)

Step-by-step explanation:

5 0

3 years ago

Given a minimum usual value of 135.8 and a maximum usual value of 155.9, determine which (1 point) of the following values would

maxonik [38]

Answer: b. 134

Step-by-step explanation:

Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.

Let x denotes a usual value.

i.e. 135.8< x < 155.9

Therefore , the interval for the usual values is [135.8, 155.9] .

If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.

Let's check all options

a. 137 ,

since 135.8< 137 < 155.9

So , it is usual.

b. 134

since 134<135.8 (Minimum value)

So , it is unusual.

c. 146

since 135.8< 146 < 155.9

So , it is usual.

d. 155

since 135.8< 1155 < 155.9

So , it is usual.

Hence, the correct answer is b. 134 .

4 0

3 years ago