Answer:
1/9
.........................
Answer:
Option (4)
Step-by-step explanation:
Area of a rectangle = Length × width
If the dimensions of the given rectangle is doubled,
Area of the new rectangle = 2(Length) × 2(width)
= 4(Length × width)
= 4(x)(x - 2)
= 4[x² - 2x]
= 4x² - 8x
Therefore, Option (4) will be the correct option.
Our system of equations is:
y = x - 4
y = -x + 6
We can solve this system of equations by substitution. We already have one equation solved for the variable y in terms of x, so we can substitute in this equivalent value for y into the second equation as follows:
y = -x + 6
x - 4 = -x + 6
To simplify this equation, we first are going to add x to both sides of the equation.
2x - 4 = 6
Next, we are going to add 4 to both sides of the equation to separate the variable and constant terms.
2x = 10
Finally, we must divide both sides by 2, to get the variable x completely alone.
x = 5
To solve for the variable y, we can plug in our solved value for x into one of the original equations and simplify.
y = x - 4
y = 5 - 4
y = 1
Therefore, your final answer is x = 5 and y = 1, or as an ordered pair (5,1).
Hope this helps!
Let x be the length of one side of the smaller square
Let y be the length of one side of the larger square
4x would be the perimeter of the smaller square, as it has 4 sides
Therefore 4x = y + 10, as the perimeter of the smaller square is 10 inches bigger than one side of the larger square.
We're going to solve this question using simultaneous equations. This means we need another equation to compare the first one to.
Since we know that one side of the larger square is 2 inches bigger than the first one, we can make the equation
y = x + 2
Know that we know the value of y in terms of x, we can introduce this value to the original equation to find:
4x = (x + 2) + 10
Therefore:
4x = x + 12
3x = 12
x = 4
Now that we know the size of the sides on the smaller square, we can figure out the size of the larger square by using our second equation (y = x + 2)
y = 4 + 2
y = 6
Therefore, the length of each side of the larger square is<u> B.6</u>
