Assume there are 365 days in a year.

1 answer:

4 0

The chance of student 1's birthday being individual is 365/365 or 100%.
Then the chance of student 2's birthday being different is 364/365.
Then it's narrowed down to 363/365 for student 3 and so on until you get all 10 students.
If you multiply all these values together, the probability would come out at around 0.88305182223 or 0.88.

To get all the same birthday you'd have to the chance of one birthday, 1/365 and multiply this by itself 10 times. This will produce a very tiny number. In standard form this would be 2.3827x10'-26 or in normal terms: 0.23827109210000000000000000, so very small.

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Step-by-step explanation:

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A survey of 1 comma 558 randomly selected adults showed that 522 of them have heard of a new electronic reader. The accompanying

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Answer with explanation:

Let p be the proportion of adults have heard of the new electronic reader.

Given claim : The accompanying technology display results from a test of the claim that 38% of adults have heard of the new electronic reader.

i.e. $p=0.38$

Then , the set of hypothesis will be :-

$H_0: p=0.38\\\\H_a:p\neq0.38$

Since, the alternative hypothesis is two tailed , so the test is two-tailed test.

Also, it is given that the sample size : $n=1558$

Number of adults showed that they have heard of a new electronic reader=522

So the sample proportion for adults have heard of the new electronic reader : $\hat{p}=\dfrac{522}{1558}\approx0.34$

The test statistic for proportion is given by :-

$z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}\\\\\\\Rightarrow\ z=\dfrac{0.34-0.38}{\sqrt{\dfrac{0.38(1-0.38)}{1558}}}\\\\\\\Rightarrow\ z=-3.25279036541\approx-3.25$