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3 years ago

Which is the equation of a line that is perpendicular to 8x + 6y = –5?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

4 0

The perpendicular line will have an equation of y=3/4x-3/4

To find this, we first have to solve our equation for slope intercept form.

8x + 6y = -5 ----> subtract 8x

6y = -8x + -5 ----> divide by 6

y = -4/3x - 5/6.

So we know the slope of this equation to be -4/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of 3/4. Since B is the only option with that slope, we know it to be the correct answer.

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A drink is made by mixing 650 ml of water with 150 ml of fruit juice.

Luda [366]

<h2>○=> <u>Correct answer</u> :</h2>

$\boxed{\color{hotpink}\tt18.75\%}$ of the drink is fruit juice

<h3>○=> <u>Steps to derive correct answer</u> :</h3>

Quantity of water in a drink = 650 ml

Quantity of fruit juice in a drink = 150 ml

Total quantity of both items in the drink :

$=\tt 650 + 150$

$\color{plum}=\tt 800 \: ml$

Thus, the total quantity of both items in the drink = 800 ml

Let the percentage of of fruit juice in the drink be x%.

Which means :

$= \tt\frac{x}{100} \times 800 = 150$

$= \tt \frac{x \times 800}{100} = 150$

$=\tt \frac{800x}{100} = 150$

$=\tt 8x = 150$

$=\tt x = \frac{150}{8}$

$\hookrightarrow\color{plum} \bold{x = 18.75\%}$

Then, the percentage of water in the drink :

$= \tt100 - 18.75$

$\color{plum}= \tt81.25\%$

Thus, the percentage of water in the drink = 81.25%

<h3>○=> <u>Therefore</u> :</h3>

▪︎Percentage of fruit juice in the drink = 18.75%

▪︎Percentage of water in the drink = 81.75%

8 0

3 years ago

Read 2 more answers

Factor the following binomail:<br><br> (2x^4 - 12x^7)

Ann [662]

Hopes this helps:

Answer: 2x^4(1-6x^3)

5 0

2 years ago

Rachel jogged a long a trail that was of 1/8 mile long . she jogged the 8 times. how meny miles trail did Rachel jog in all

galben [10]

It's 1 mile. She ran an 8th if an mile. If the ran 1/8 of a mile 8 times, it adds up to 1 mile.

5 0

3 years ago

Suppose that a box contains r red balls and w white balls. Suppose also that balls are drawn from the box one at a time, at rand

dybincka [34]

Answer: Part a) $P(a)=\frac{1}{\binom{r+w}{r}}$

part b) $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}$

Step-by-step explanation:

The probability is calculated as follows:

We have proability of any event E = $P(E)=\frac{Favourablecases}{TotalCases}$

For part a)

Probability that a red ball is drawn in first attempt = $P(E_{1})=\frac{r}{r+w}$

Probability that a red ball is drawn in second attempt= $P(E_{2})=\frac{r-1}{r+w-1}$

Probability that a red ball is drawn in third attempt = $P(E_{3})=\frac{r-2}{r+w-1}$

Generalising this result

Probability that a red ball is drawn in [tex}i^{th}[/tex] attempt = $P(E_{i})=\frac{r-i}{r+w-i}$

Thus the probability that events $E_{1},E_{2}....E_{i}$ occur in succession is

$P(E)=P(E_{1})\times P(E_{2})\times P(E_{3})\times ...$

Thus $P(E)$ = $\frac{r}{r+w}\times \frac{r-1}{r+w-1}\times \frac{r-2}{r+w-2}\times ...\times \frac{1}{w}\\\\P(E)=\frac{r!}{(r+w)!}\times (w-1)!$

Thus our probability becomes

$P(E)=\frac{1}{\binom{r+w}{r}}$

Part b)

The event " r red balls are drawn before 2 whites are drawn" can happen in 2 ways

1) 'r' red balls are drawn before 2 white balls are drawn with probability same as calculated for part a.

2) exactly 1 white ball is drawn in between 'r' draws then a red ball again at $(r+1)^{th}$ draw

We have to calculate probability of part 2 as we have already calculated probability of part 1.

For part 2 we have to figure out how many ways are there to draw a white ball among (r) red balls which is obtained by permutations of 1 white ball among (r) red balls which equals $\binom{r}{r-1}$

Thus the probability becomes $P(E_i)=\frac{\binom{r}{r-1}}{\binom{r+w}{r}}=\frac{r}{\binom{r+w}{r}}$

Thus required probability of case b becomes $P(E)+ P(E_{i})$

= $P(b)=\frac{1}{\binom{r+w}{r}}+\frac{r}{\binom{r+w}{r}}\\\\$

7 0

3 years ago

Hello! can you please, help me by finding some missing angles.

yuradex [85]

Answer:

Going horizontally,

Q1 a) x = 133°

Q1 b) x = 59°

Q1 c) x = 189°

Q1 d) x = 32°

Q1 e) x = 72°

Q1 f) x = 36°

Q2 a) x = 53°

Q2 b) x = 94°

Q2 c) x = 10°

Workings out:

To work out the interior angles, you need to know that angles on a straight line add up to 180°. In addition, you also need to know that angles around a point add up to 360°. When you need to find a missing angle, if the angle is on a line or in a triangle, take whatever value/values the angle/angles you have are and take it away from 180°. If the angle is around a point, (or in a square, where all angles are the same anyway) add however many values you have for the angles then take that away from 360°. Hope this helps! :)

8 0

3 years ago