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ohaa [14]
3 years ago
9

Which is the equation of a line that is perpendicular to 8x + 6y = –5?

Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0

The perpendicular line will have an equation of y=3/4x-3/4

To find this, we first have to solve our equation for slope intercept form.

8x + 6y = -5 ----> subtract 8x

6y = -8x + -5 ----> divide by 6

y = -4/3x - 5/6.

So we know the slope of this equation to be -4/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of 3/4. Since B is the only option with that slope, we know it to be the correct answer.

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Hello.

First of all, let the number be t.

8 times t can be written like this:

\mathrm{8t}

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\boxed{imperturbability}

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#20 four times the sum of number. and 15 is a least20. Let X represent the number. :find ball possible values for X
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For this case what we have to take into account is the following variable:
 x = represent the unknown number
 We now write the following inequality:
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 Answer:
 
all possible values for X are:
 
[-10, inf)
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