Which is the equation of a line that is perpendicular to 8x + 6y = –5?

Mathematics

1 answer:

IrinaVladis [17]3 years ago

4 0

The perpendicular line will have an equation of y=3/4x-3/4

To find this, we first have to solve our equation for slope intercept form.

8x + 6y = -5 ----> subtract 8x

6y = -8x + -5 ----> divide by 6

y = -4/3x - 5/6.

So we know the slope of this equation to be -4/3. Since perpendicular lines have opposite and reciprocal slopes, we know we can simply flip the fraction and make it a negative to get the new slope of 3/4. Since B is the only option with that slope, we know it to be the correct answer.

You might be interested in

I need help asap due tonight

riadik2000 [5.3K]

Answer:

Step-by-step explanation:

multiply 10 by w and 3

equation becomes 10w+30=70

subtract 30 by both sides

equation becomes 10w=40

divide both sides by 10

equation becomes w=4

your answer is 4!

7 0

2 years ago

Read 2 more answers

Solve for x:(-771)+x=0

NeX [460]

Answer:

x=771

Step-by-step explanation:

−771 + x = 0

x − 771 = 0

x − 771 + 771 = 0 + 771

4 0

2 years ago

Simplify this: log√24+ log6

Kitty [74]

simplifying $log\sqrt{24}+log6$ we get $log(12\sqrt{6})$

Step-by-step explanation:

We need to simplify: $log\sqrt{24}+log6$

Solving:

Applying the rule:

log a + log b = log(ab)

$log\sqrt{24}+log6\\=log(6\sqrt{24})\\\sqrt{24} = \sqrt{2*2*2*3} =\sqrt{2^2*6} =\sqrt{2^2} \sqrt{6}=2\sqrt{6}\\ Putting\,\,value:\\=log(6*2\sqrt{6})\\=log(12\sqrt{6})$