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ziro4ka [17]
3 years ago
9

F(x)=x^3+4x^2+x-6 What are the real zeros

Mathematics
1 answer:
Over [174]3 years ago
6 0

Happy New Year from MrBillDoesMath!

Answer:

   1, -2, -3

Discussion:

The real roots of the polynomials are factors of the last term (6) divided by the first term (1). The factors of 6/1 or 6 are 1,2,3, and 6. I found by substitution that x= 1 was a solution, divided the polynomial by x-1, came up with a quadratic (x^2 + 5x + 6), and found the remaining roots via the quadratic formula.


Thank you,

MrB



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Step-by-step explanation:

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