F(x)=x^3+4x^2+x-6 What are the real zeros

Mathematics

1 answer:

Over [174]3 years ago

6 0

Happy New Year from MrBillDoesMath!

Answer:

1, -2, -3

Discussion:

The real roots of the polynomials are factors of the last term (6) divided by the first term (1). The factors of 6/1 or 6 are 1,2,3, and 6. I found by substitution that x= 1 was a solution, divided the polynomial by x-1, came up with a quadratic (x^2 + 5x + 6), and found the remaining roots via the quadratic formula.

Thank you,

MrB

You might be interested in

Pls help me also i like mr.bubz

Serggg [28]

you Answer is:

x = − 27

6 0

3 years ago

Read 2 more answers

What is the difference between a 30° angle and a -30° angle?

ipn [44]

Answer:

See below

Step-by-step explanation:

A 30° angle is measured 30° counterclockwise while a -30° angle is measured 30° clockwise. Therefore, you can say -30°=360-30°=330° because 30° is a reference angle located in Quadrant IV.

7 0

3 years ago

Solve x2 - 8x - 9 = 0. Rewrite the equation so that it is of the form x2 + bx = c.

barxatty [35]

Answer:

x=9,-1 and $x^2+(-8)x=9$

Explanation:

we have been given with the quadratic equation $x^2-8x-9$

we compare the given quadratic equation with general quadratic equation

general quadratic is $ax^2+bx+c=0$

from given quadratic equation a=1,b= -8,c= -9

substituting these values in the formula for discriminant $D=b^{2}-4ac$

$D=(-8)^2-4(1)(-9)=100$

Now, to find the value of x

Formula is $x=\frac{-b\pm\sqrt{D}}{2a}$

Now, substituting the values we will get

$x=\frac{-(-8)\pm\sqrt{100}} {2}= \frac{8\pm10}{2}=9,-1$

And rewritting the given equation by shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of

$x^2+bx=c$