Set x as adult tickets.
Set y as children's tickets.
x + y = 15
30x + 20y = 270
Solve for x in the first equation.
x + y = 15
x = 15 - y
Plug this into the second equation.
30x + 20y = 270
30(15 - y) + 20y = 270
450 - 30y + 20y = 270
450 - 10y = 270
-10y = -180
y = 18
If there is 18 childrens tickets, there should be -3 adult tickets.
This is impossible, and this impossible answer occured because the question is written wrong.
There are a total of 15 tickets
The smallest costing ticket is the childrens ticket, which costs 20$.
If he only bought children tickets, this would be 20x15 which is 300$.
300$ is over 270$, which makes the question impossible.
Hello from MrBillDoesMath!
Answer:
I think your formula (2y/x2) is equivalent to
(2*y)/(x^2) where x^2 means x-squared.
If so, then
(2*y)/(x^2) = (2*3)/(4*4) = 6/16 = 3/8
Thank you,
MrB
The answer is N=6 but first you have to simplify the problem try that '
The answer is 3! You got this!
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