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ivolga24 [154]
2 years ago
15

If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)​

Mathematics
1 answer:
worty [1.4K]2 years ago
6 0
If sec 0 = 8x then tan 0 = 8/x ( x does not equal to 0), than the value of 16 ( x squared - 1/x squared) is: 1/4

Answer: 1/4
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3241004551 [841]

Answer:

KPF = 9 and H = 129

Step-by-step explanation:

An inscribed quadrilateral in a circle has all diagonal angles add up to 180, so we can use this to find the angles of the quadrilateral.  

H= 180-EPK and K = 180-E so H = 129 and K = 60

Now PF and EH are parallel, so PE is a transversal.   That means FPE = 180 - E = 60.  Now it's pretty easy to solve for KPF = FPE - EPK = 60 - 51 = 9.

Let me know if you don't see how I did any of this and I'll be happy to explain it..

3 0
3 years ago
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Alenkasestr [34]

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6 0
3 years ago
Lusia ran 3 2/3 kilometers in 1/3 of an hour. If speed is distance over time, calculate lusia's speed.
Romashka [77]
In the question, they give you the formula for speed...

speed = distance / time

They also give you the distance and the time, so all we have to do is stick them into the equation...

speed =  3 2/3 Km / 1/3 hour
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To divide the fractions, first we need to convert 3 2/3 into an improper fraction

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now we multiply 11/3 x the reciprocal of the divisor 1/3.  The reciprocal just means flip the numerator and denominator

speed = 11/3 x 3/1
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3 years ago
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stellarik [79]

Answer:

The first zero after decimal point and 4 only

Step-by-step explanation:

Despite having 5 decimal points, the rules of significant figures dictate that unless there is a digit other than zero after, the only significant numbers are those that come before zero. For this case, the significant digits are only 0.04 but if it was 0.0400005 then all the other zeros would have also be considered significant.

5 0
3 years ago
What is the repeating or terminating decimal that is equivalent to 11/36
Oduvanchick [21]

Answer:

0.30555555....

Step-by-step explanation:

(The fives keep on coming, this is a repeating decimal.)

3 0
3 years ago
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