2 years ago

If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)

1 answer:

6 0

If sec 0 = 8x then tan 0 = 8/x ( x does not equal to 0), than the value of 16 ( x squared - 1/x squared) is: 1/4

Answer: 1/4

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If 4 (log3 1/27)=X what is the value of X

givi [52]

$4(log _{3} 1/27) =x$
$log _{3} \frac{1}{27}^4 =x$

Now remember: $b^y=x \\ equals \\ log _{b}x=y$

$3^x = \frac{1}{27}^4$
$3^x = \frac{1}{531441}$
$log _{3} \frac{1}{531441} =x$
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Solnce55 [7]

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