2 years ago

If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)

1 answer:

6 0

If sec 0 = 8x then tan 0 = 8/x ( x does not equal to 0), than the value of 16 ( x squared - 1/x squared) is: 1/4

Answer: 1/4

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shepuryov [24]

Answer:

B. $(5+2)^{2} > 5^2 + 2^2$

Step-by-step explanation:

The inequality "B" is correct because when you simplify it, you can see that it holds true:

$7^{2} > 25 + 4$

49 > 29

49 is indeed greater than 29, making this inequality true.

8 0

3 years ago

Westkost [7]

Answer:

Step-by-step explanation:

$9*8=72\\0.5*6*8=24\\10*9=90\\72+24+90=186 m^{2}$

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3 years ago

Ivenika [448]

The person above me is correct

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3 years ago

mojhsa [17]

As long as 2 opposite sides are the same and the other two opposite sides are the same. eg. 6,6,2 &2 / 1,1,7 & 7 and so on

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3 years ago

ad-work [718]

Answer:

- 5

Step-by-step explanation:

Note that - (- 12) = + 12

Thus

- 17 - (- 12) = - 17 + 12 = - 5

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8 0

3 years ago

If 8x = sec θ and 8/x= tan 0. Find the value of 16(x^2 - 1/x^2)​