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1 year ago

15

The Formula for the volume of a right square pyramid is given down below, where a is the side length of the base and h is the he

ight.
V= 1/3a^2h
Rewrite the formula and solve for a
PLEASE ANSWER WILL GIVE BRAINLIEST IF CORRECT

1 answer:

NeTakaya1 year ago

6 0

Answer: Is it B? I hope it helps you :)

Step-by-step explanation:

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Carey measured a city park and made a scale drawing. In real life, the soccer field is 99 meters long. It is 33 millimeters long

Leokris [45]

99/33= 3

All you need to do is divide the real soccer felid by the scale drawing. Don't let the meters and the millimeters confuse you- it will still give you the right scale even though they are different units of measure.

1 millimeter= 3 meters

I hope this helps!
<em>~kaikers</em>

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3 years ago

Estimate the value of √2

marusya05 [52]

Answer:

B. 0.50

Step-by-step explanation:

It claims to estimate. Square root of 2 would be somewhere around 1. Square root of 5 would be somewhere around 2. Then you divide, 1/2, and that should equal 0.50.

I hope this is correct!

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2 years ago

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the morning tempature was -7C. By noon the tempature was 8C. how many degrees has the tampature risen

ddd [48]

It has risen 15 degrees .....

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2 years ago

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How do you slove 3x+4y=8 in steps

gavmur [86]

<span><span><span>3x</span>+<span>4y</span></span>=8
</span>Add -4y to both sides
<span><span><span><span>3x</span>+<span>4y</span></span>+<span>−<span>4y</span></span></span>=<span>8+<span>−<span>4y</span></span></span></span><span><span>3x</span>=<span><span>−<span>4y</span></span>+8
</span></span>Then you divide both sides by 3
<span><span><span>3x/</span>3</span>=<span><span><span>−<span>4y</span></span>+8/</span>3</span></span><span>x=<span><span><span><span>−4/</span>3</span>y</span>+<span>8/3
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2 years ago

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is $\frac{1}{6}$ which is on friday and then $\frac{1}{4}$ on monday.

Rest distance which is $\frac{6}{8}$ on wednesday.

Hence, Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

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3 years ago

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