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3 years ago

What is the x value such that y =15 - 3x and y = 0? Please explain how you got this answer.

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

3 0

Answer:

x=5

Step-by-step explanation:

So how i came about to get this answer, was

y=15-3x

y=15-3(5)

y=15-15

y=0

I found five by testing out different numbers for x such as 1 2 3 4, but when i got to five, that was where i got the answer, as shown above.

Do not forget about PEMDAS

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Given:
adults = x
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female = (7x + 1)/2
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3 years ago

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3 years ago

-5(5-3v)=-115 Helpp me please

prisoha [69]

we start by opening the brackets so it will be -25 plus 15 v is equals to 115. negative times a negative is a positive so -5 times -3 we we have gotten positive 15v there I hope you understood so our new equation is -25 + 15v is equals to 115 collect the like terms 15v is equals to 115 + 25 15 v is equals to 140 divide both sides by 15 so v is equals to 9 and 1/3

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Students attending the University of Florida can select from 130 major areas of study. A student's major is identified in the re

omeli [17]

Answer:

1. 8385 double majors

2. 18252 major codes

3. 8515 codes

4. Yes

Step-by-step explanation:

Given

Major areas = 130

Alphabets = 26

There are 130 major areas in the university.

To get a double majors, means one select any of two of the major areas in the university.

i.e. just 2 alphabets are needed

Number of Double Majors = 130C2

130C2 = 130!/(128!*2!)

130C2 = 130 * 129/2

130C2 = 8385.

Number of major codes available = Number of 2 digit codes + Number of 3 digit codes

Number of 2 digit codes = 2 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

So, number of 2 digit codes = 26 * 26 = 676.

Number of 3 digit codes = 3 alphabets

There are 26 ways of selecting the first letter

There are 26 ways of selecting the second letter

There are 26 ways of selecting the third letter

So, number of 3 digit codes = 26 * 26 * 26 = 17576

Thus, number of major codes = 17576 + 676 = 18252

Number of codes to identify a student with either a single major or double major

Number off single major codes = number of major areas = 130

Number of double major codes = 8385

Total = 130 + 8385 = 8515

d. From the solutions above, Yes there are enough codes available to identify all single and double majors at the university

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Answer:

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