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vichka [17]
2 years ago
14

What is the recursive formula of the geometric sequence? 1, 5, 25, 125, 625, ...

Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

The recursive formula of the geometric sequence is given by option D; an = (1) × (5)^(n - 1) for n ≥ 1

<h3>How to determine recursive formula of a geometric sequence?</h3>

Given: 1, 5, 25, 125, 625, ...

  • first term, a = 1

  • Common ratio, r = 25/5

= 5

  • n = number of terms

an = a × r^(n - 1)

= 1 × 5^(n - 1)

an = (1) × (5)^(n - 1) for n ≥ 1

Learn more about recursive formula of geometric sequence:

brainly.com/question/10802330

#SPJ1

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Write a polynomial function of least degree with integral coefficients that has the
frutty [35]

A polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Given

Given zeros are 3i, -1  and 0

complex zeros occurs in pairs. 3i is one of the zero

-3i is the other zero

So zeros are 3i, -3i, 0 and -1

Now we write the zeros in factor form

If 'a' is a zero then (x-a) is a factor

the factor form of given zeros

\:\left(x-3i\right)\left(x-\left(-3i\right)\right)\left(x-0\right)\left(x-\left(-1\right)\right)\\\left(x-3i\right)\left(x+3i\right)\left(x-0\right)\left(x+1\right)

Now we multiply it to get the polynomial

x\left(x-3i\right)\left(x+3i\right)\left(x+1\right)\\x\left(x^2+9\right)\left(x+1\right)\\x\left(x^3+x^2+9x+9\right)\\x^4+x^3+9x^2+9x

polynomial function of least degree with integral coefficients that has the

given zeros  f(x)=x^4+x^3+9x^2+9x

Learn more : brainly.com/question/7619478

6 0
3 years ago
Write each expression using n as your variable.
frozen [14]
C3=n
N x 2 - 6 + 2
N < (6x8) - 10
8 0
2 years ago
Graph the function.<br> Y=[1/2x-1]
Scilla [17]
This should help you

3 0
3 years ago
Find the value of sin30+tan^(2)60+sec^(2)45​
xenn [34]

Answer:

Step-by-step explanation:

sin 30+tan²(60)+sec²(45)

=1/2+ (√3)^2+(√2)²

=1/2+3+2

=5 1/2

=5.5

3 0
3 years ago
Write a recursive and an explicit formula to represent the following sequence 52, 40, 28, 16,...
horrorfan [7]

Answer:

Explicit tn = 52 + (n - 1)*(-12)

Recursive = tn = t(n - 1) - 12

Step-by-step explanation:

The difference between term n and term n - 1 is can be found by taking the difference between and 2 consecutive terms.

t3 = 28

t2 = 40

d = t3 - t2

d = 28 - 40

d = - 12

Explicit

tn = a1 + (n - 1)*d

a1 = 52

d = - 12

tn = 52 + (n - 1)*(-12)

<em><u>Example</u></em>

Find t5

t5 = 52 + (5 - 1)*(-12)

t5 = 52 + 4 * - 12

t5 = 52 - 48

t5 = 4

Recursive

tn = t(n - 1) - 12

<em><u>Example</u></em>

t5 = t4 - 12

t5 = 16 - 12

t5 = 4 just as it did before.

5 0
3 years ago
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