Answer:11
Step-by-step explanation:14-3=11
Given:
Atul has
lb of candy.
Jose has
lb of candy.
Maria has
lb less than Jose.
To find:
How many more pounds of candy does Atul have than Maria?
Solution:
Since, Maria has
lb less than Jose, therefore
Maria has =
lb
Maria has =
lb
Maria has =
lb
Difference between the candies Atul and Maria have.
Difference =
lb
Difference =
lb
Difference =
lb
Therefore, Atul have
lb of candy more than Maria.
(x+20)-(x+1)=18
x+20-x-1=18
19=18
It has no solution
No...standard form cannot have fractions
2/3x - 1/3y = 2....multiply by common denominator of 3 to get rid of fractions
2x - y = 6 <== standard form