Answer:
Step-by-step explanation:
we know that
The quadratic equation in vertex form is equal to
where
a is the leading coefficient
(h,k) is the vertex of the quadratic equation
Remember that
In a quadratic equation the turning point is the same that the vertex
so
(h,k)=(-1,-16)
substitute
we have one zero at (-3,0)
substitute and solve for a
substitute
Convert to standard form
Answer:
y^1 = log5/log9 & y^2 = 7 - 3x
So, we will be using point-slope form to construct this equation.
Point-slope form's general formula is as follows:
M is the slope,
Y₁ is the Y-coordinate of the point
X₁ is the X- coordinate of the point.
So, our slope is 3 (since the equation is given in slope-intercept form)
Our Y₁ is 7 and out X₁ is 4
So, now we just plug our numbers into the equation.
There's your equation.
Hope this helps!
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<h3>Answer : 5</h3>
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<h3>Known</h3>
y = 5x + 4
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<h3>Question</h3>
slope = gradient (m)
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<h3>Known that the formula of equation of the line is</h3>
y = mx + c
So, the m is 5 and so the slope is 5
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