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SSSSS [86.1K]
2 years ago
11

For what values of x is the equation true? (Form 1st!) x^2-4x=32

Mathematics
1 answer:
Alexandra [31]2 years ago
8 0

Answer:

It can be solved in many forms

one by replacing each point to see which one satisfy the equation or by using quadratic formula

so the right answer is the fourth one

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Answer:

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The value of the Wronskian is \bold{W=-3e^{7x}}

Step-by-step explanation:

We can calculate the Wronskian using the fundamental solutions that we are provided and their corresponding the derivatives, since the Wroskian is defined as the following determinant.

W = \left|\begin{array}{cc}y&z\\y'&z'\end{array}\right|

Thus replacing the functions of the exercise we get:

W = \left|\begin{array}{cc}e^{5x}&e^{2x}\\5e^{5x}&2e^{2x}\end{array}\right|

Working with the determinant we get

W = 2e^{7x}-5e^{7x}\\W=-3e^{7x}

Thus we have found that the Wronskian is not 0, so the solutions are linearly independent.

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