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Oliga [24]
3 years ago
8

Which transformation takes Figure A to Figure B in Pair 2:

Mathematics
1 answer:
bearhunter [10]3 years ago
5 0

Answer:

reflection

Step-by-step explanation:

if you look at it, its like its mirrored itself, so its reflection

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Your friend asks you to make friendship bracelets and will give you 6 nickels for the first bracelet. You agree to help if she m
just olya [345]
For n=1, the result is 6

for n=2, the result is 36
so it is
an=6ⁿ

8th bracelet is 6⁸=1679616 nickles (about $83980.8)
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Which rate had the same unit rate as 300 words in 4 minutes? Circle all correct answers
rjkz [21]

Answer:

B) 450 words in 6 minutes

Step-by-step explanation:

450 divided by 6 is equal to 75 which makes 75 words per minute. Then if you divide 300 by 4 it also is 75 words per minute.

3 0
4 years ago
PLEASEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE HELPPPP
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Answer:

C) 20,000

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3 years ago
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What is the difference? StartFraction x 5 Over x 2 EndFraction minus StartFraction x 1 Over x squared 2 x EndFraction StartFract
Troyanec [42]

The difference of the given fraction is expressed as \frac{x^2+4x-1}{x(x+2)}

Given the expression:

  • \frac{x+5}{x+2}-\frac{x+1}{x^2+2x} \\

Take the LCM of the fraction to have:

=\frac{x+5}{x+2}-\frac{x+1}{x(x+2)} \\=\frac{x(x+5)-(x+1)}{x(x+2)} \\=\frac{x^2+5x-x-1}{x(x+2)}\\=\frac{x^2+4x-1}{x(x+2)}

Hence the difference of the given fraction is expressed as \frac{x^2+4x-1}{x(x+2)}

Learn more on fractions here; brainly.com/question/78672

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1 + 10 square theta (1 - sin square theta is equals to 1<br>​
KengaRu [80]

Let's prove

\boxed{\sf 1+tan^2\theta(1-sin^2\theta)=1}

LHS

\\ \sf\longmapsto 1+tan^2\theta(1-sin^2\theta)

\\ \sf\longmapsto 1+\dfrac{sin^2\theta}{cos^2\theta}(1-sin^2\theta)

\\ \sf\longmapsto \dfrac{cos^2\theta+sin^2\theta}{cos^2\theta}(1-sin^2\theta)

\\ \sf\longmapsto \dfrac{1}{cos^2\theta}(1-sin^2\theta)

\\ \sf\longmapsto \dfrac{1-sin^2\theta}{cos^2\theta}

\\ \sf\longmapsto \dfrac{1-sin^2\theta}{1-sin^2\theta}

\\ \sf\longmapsto 1

Hence provee

3 0
3 years ago
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