An airplane starts from rest and undergoes a uniform acceleration of 11.7 m/s2 for 23.6 s seconds before leaving the ground. Wha
1 answer:
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Answer:
Both objects are packed equally tightly.
Explanation:
For Substance R we have
mass = 10 g
Volume = 22 cubic cm
So we know that density is defined as
here we have
For substance S we have
mass = 25 g
Volume = 55 cubic cm
So we know that density is defined as
here we have
So here both have same density
so correct answer would be
Both objects are packed equally tightly.
Answer:
The kinetic coefficient of friction between the box and the floor is 1.020.
Explanation:
Let suppose that box is on horizontal ground. According to the Newton's Laws, an object has a net acceleration of zero when either is at rest or moves at constant velocity. Friction is a reaction to the external force that moves the box. Hence, the equation of equilibrium for the 20-Kg box is:
(Eq. 1)
Where:
- External force, measured in newtons.
- Friction force, measured in newtons.
If we know that , then the magnitude of the kinetic friction force is:
In addition, friction force is represented by the following formula:
(Eq. 2)
Where:
- Kinetic coefficient of friction, dimensionless.
- Mass, measured in kilograms.
- Gravitational acceleration, measured in meters per square second.
Now we clear the kinetic coefficient of friction:
If we know that ,
and
, then the kinetic coefficient of friction is:
The kinetic coefficient of friction between the box and the floor is 1.020.