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3 years ago

why is it important to create pictorial and physical models before trying to solve an equation, solving a physics problem

Physics

2 answers:

Romashka [77]3 years ago

5 0

Many fundamental laws of physics and chemistry can be formulated when doing this.

amm18123 years ago

3 0

The pictorial and physical model help in many ways when we solve physics problems.

A pictorial representation of data refers to the presentation of data in different symbols or pictures of different objects.It gives the idea of deeper understanding of the problem. It makes the data clear and useful,and helps in comparing it with different parameters.

A physics problem is not always full with digits and equations.Sometimes a problem require higher understanding .Physical model plays a crucial role in this situation.It eradicates all the ambiguity and provides the idea to solve the problems pragmatically.

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What is the cell emf for the concentrations given? Express your answer using two significant figures.

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Complete Question

A voltaic cell is constructed with two $Zn^{2+}$ $- Zn$ electrodes. The two cell compartment have $[Zn^{2+}] = 1.6 \ M$ and $[Zn^{2+}] = 2.00*10^{-2} \ M$ respectively.

What is the cell emf for the concentrations given? Express your answer using two significant figures

Answer:

The value is $E = 0.06 V$

Explanation:

Generally from the question we are told that

The concentration of $[Zn^{2+}]$ at the cathode is $[Zn^{2+}]_a = 1.6 \ M$

The concentration of $[Zn^{2+}]$ at the anode is $[Zn^{2+}]_c = 2.00*10^{-2} \ M$

Generally the the cell emf for the concentration is mathematically represented as

$E = E^o - \frac{0.0591}{2} log\frac{[Zn^{2+}]a}{ [Zn^{2+}]c}$

Generally the $E^o$ is the standard emf of a cell, the value is 0 V

$E = 0 - \frac{0.0591}{2} * log[\frac{ 2.00*10^{-2}}{1.6} ]$

=> $E = 0.06 V$

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