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pentagon [3]
3 years ago
14

why is it important to create pictorial and physical models before trying to solve an equation, solving a physics problem

Physics
2 answers:
Romashka [77]3 years ago
5 0
Many fundamental laws of physics and chemistry can be formulated when doing this.
amm18123 years ago
3 0

The pictorial and physical model help in many ways when we solve physics problems.

A pictorial representation of data refers to the presentation of data in different symbols or pictures of different objects.It gives the idea of deeper understanding of the problem. It makes the data clear and useful,and helps in comparing it with different parameters.

A physics problem is not always full with digits and equations.Sometimes a problem require higher understanding .Physical model plays a crucial role in this situation.It eradicates all the ambiguity and provides the idea to solve the problems pragmatically.

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babymother [125]

We can get water from the sweat and exhaled breath of the people present in the space station.

<h3>How would you get water?​</h3>

We can get water from the sweat and exhaled breath. The water we drink is recycled from the sweat and exhaled breath of the people present in the space station which was collected through  condensation on the Space Station's walls.

So we can conclude we can get water from the sweat and exhaled breath of the people present in the space station.

Learn more about water here: brainly.com/question/1313076

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6 0
2 years ago
What is the difference between aerial photography and satellite imagery
Pachacha [2.7K]
<span>The difference is that an aerial photo is a photo of an area and satellite
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7 0
4 years ago
Read 2 more answers
What is the most common way to organize data in a experiment
kobusy [5.1K]

A chart because you can set it up anyway you want

5 0
4 years ago
What is the magnitude of your displacement when you follow directions that tell you to walk 225 m in one direction, make a 90° t
Gekata [30.6K]

Start by facing East. Your first displacement is the vector

<em>d</em>₁ = (225 m) <em>i</em>

Turning 90º to the left makes you face North, and walking 350 m in this direction gives the second displacement,

<em>d</em>₂ = (350 m) <em>j</em>

Turning 30º to the right would have you making an angle of 60º North of East, so that walking 125 m gives the third displacement,

<em>d</em>₃ = (125 m) (cos(60º) <em>i</em> + sin(60º) <em>j</em> )

<em>d</em>₃ ≈ (62.5 m) <em>i</em> + (108.25 m) <em>j</em>

The net displacement is

<em>d</em> = <em>d</em>₁ + <em>d</em>₂ + <em>d</em>₃

<em>d</em> ≈ (287.5 m) <em>i</em> + (458.25 m) <em>j</em>

and its magnitude is

|| <em>d</em> || = √[ (287.5 m)² + (458.25 m)² ] ≈ 540.973 m ≈ 541 m

7 0
3 years ago
How much Power is needed to lift a 200 N block
vova2212 [387]

Answer:

10 W

Explanation:

P = F x v

F = 200N

v = x2 - x1 / t

  = 6 - 3 / 60

  = 3 / 60

  = 1 / 20

  = 0.05 m/s

P = 200 x 1/20

  = 10 W

4 0
2 years ago
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