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Aleks04 [339]
3 years ago
14

A rectangle's length is three times its width. Let w denote the rectangle's width. What polynomial represents the rectangle's ar

ea?
Mathematics
1 answer:
Ket [755]3 years ago
7 0
<span>A = l x w
Since 
l = 3w

Substitute the l with 3w
The formula will be

A = 3w + w
A = 4w

An example:
The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle.   Since the geometric formula for perimeter is: </span>
P= 2 (l + w) 
L = 2w – 4 cm 
W =?   
Derivation and solution: 
34 = 2 (2w - 4) + 2w <span>
34 =  4w – 8 + 2w</span> 
42 = 6w 42/6 = w 
W = 7 cm   

34 = 2l + 2(7) 
34 = 2l + 14 
2l = 34 – 14 
2l = 20 
L = 20/2 
L = 10 cm<span> <span>
</span></span>

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Step-by-step explanation:

6 0
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Annette [7]

Answer:

I believe the answer would be 1,706.1

Step-by-step explanation:

Since the problem is a fraction, it would be easier to covert it to a decimal. This is made simple since the fraction is out of ten. Now, the number should look like this: 36.3

Now let's do long division.

Now we have answer of 1706.1

We have one more step. Since there is one number behind the decimal point in 36.3, we have to put one number behind the decimal point in our answer.

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I hope you understand after I have explained. If you have any other troubles, tell me.

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3 years ago
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5 0
3 years ago
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The area of the regular hexagon is 169.74 ft2 what is the perimeter, rounded to the nearest tenth
Bess [88]

Answer:

Perimeter of given regular hexagon is <em>48.5 ft</em>.

Step-by-step explanation:

Let <em>ABCDEF</em> be the regular hexagon as shown in the attached figure.

<em>O</em> be the intersection point of the diagonals <em>EB</em>, <em>FC </em>and <em>AD</em>.

As per the property of regular hexagon, all the 6 triangles formed are equilateral triangles.

In other words,

\triangle EOD, \triangle DOC, \triangle BOC, \triangle AOB, \triangle AOF , \triangle FOE are equilateral \triangle s.

Area of an equilateral \triangle is defined as :

\dfrac{\sqrt{3}}{4} \times a^{2}

Where <em>a </em>is the side of \triangle.

Area of hexagon = 6 \times \dfrac{\sqrt{3}}{4}\times a^{2}

We are given that area of hexagon = 169.74 ft^{2}

Let <em>s </em>be the side of hexagon.

\Rightarrow 6 \times \dfrac{\sqrt{3}}{4}s^{2} = 169.74 ft^{2}\\\Rightarrow s = 8.08 ft

A regular Hexagon is made up of 6 equal sides, so

Perimeter of a regular hexagon = 6 \times side

Perimeter = 6 \times 8.08

\Rightarrow 48.5 ft

So, perimeter of given regular hexagon is 48.5 ft.

6 0
3 years ago
The measures of the angles of a triangle are shown below. Solve for x
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Step-by-step explanation:

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3 years ago
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