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Aleks04 [339]
3 years ago
14

A rectangle's length is three times its width. Let w denote the rectangle's width. What polynomial represents the rectangle's ar

ea?
Mathematics
1 answer:
Ket [755]3 years ago
7 0
<span>A = l x w
Since 
l = 3w

Substitute the l with 3w
The formula will be

A = 3w + w
A = 4w

An example:
The given known values are: Length of 4 cm Width is unknown Perimeter is 34 cm Find the dimensions of the rectangle.   Since the geometric formula for perimeter is: </span>
P= 2 (l + w) 
L = 2w – 4 cm 
W =?   
Derivation and solution: 
34 = 2 (2w - 4) + 2w <span>
34 =  4w – 8 + 2w</span> 
42 = 6w 42/6 = w 
W = 7 cm   

34 = 2l + 2(7) 
34 = 2l + 14 
2l = 34 – 14 
2l = 20 
L = 20/2 
L = 10 cm<span> <span>
</span></span>

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3 0
3 years ago
Which types of quadrilaterals have congruent diagonals?
Svetlanka [38]
The answer to this is rectangle and square
4 0
3 years ago
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Help me the questions and answer choices are in the picture
Anika [276]
<span>Using the Triangle Inequality Theorem

</span><span>The sum of two side lengths of a triangle is always greater than the third side
</span>
first one: 6, 22 , 10
6 + 22   > 10 :  yes
22 + 10 > 6   :  yes
6 + 10 > 22   :  No because 16 < 22
These 3 lengths could NOT be lengths of sides of a triangle

second one: 8 , 15 , 22
8 + 15   > 22 :  yes
15 + 22 > 8   :  yes
8 + 22 > 15   :  yes
These 3 lengths could  be lengths of sides of a triangle

Answer:
Second option
8 cm, 15 cm, 22 cm
3 0
3 years ago
In the given figure ABCD is a tripepizeum with AB||CD. If AO = x-1, CO = BO = x+1 and CD = x+4. Find the value of x.
Hitman42 [59]

\longmapstoThe value of "x" is 5.

\large\underline{\sf{Solution-}}

Given that,

A trapezium ABCD in which AB || CD such that

  • AO = x - 1

  • CO = BO = x + 1

  • OD = x + 4

Now,

\rm In \: \triangle  \: AOB  \: and \: \triangle \:  COD

\rm  \: \angle  \: AOB  \: and \: \angle \:  COD \:  \:  \{vertically \: opposite \: angles \}

\rm  \: \angle  \:ABO  \: and \: \angle \:  CDO \:  \:  \{alternate \: interior \: angles \}

\bf \: \triangle  \: AOB \:  \sim \:  \triangle  \: COD \:  \:  \:  \{AA \: similarity \}

\bf\longmapsto\:\dfrac{AO}{CO}  = \dfrac{BO}{DO}

\rm \longmapsto\:\dfrac{x - 1}{x + 1}  = \dfrac{x + 1}{x + 4}

\rm \longmapsto\:(x - 1)(x + 4) =  {(x + 1)}^{2}

\rm \longmapsto\: {x}^{2} - x + 4x - 4 =  {x}^{2} + 1 + 2x

\rm \longmapsto\: 3x - 4 =  1 + 2x

\rm \longmapsto\: 3x  -  2x=  1 +4

\bf\longmapsto \:x = 5

7 0
3 years ago
I tried answering this but I don't think its right ​
iogann1982 [59]
Yeah that is correct. 3/4 is equal to .75
7 0
3 years ago
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