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olya-2409 [2.1K]
3 years ago
9

Xander rolls two 6-sided number cubes. What is the theoretical probability of rolling an even number on the first cube and a num

ber divisible by 3 on the
second cube?
Mathematics
1 answer:
NeX [460]3 years ago
7 0

Answer:

1/6

Step-by-step explanation:

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How do I find this, what’s the formula to find the 20th term and can anyone explain the formula? Will award brainliest
harina [27]

Answer:

  • f(n) = n^2 +1
  • f(20) = 401

Step-by-step explanation:

The first differences of the sequence are ...

  • 5-2 = 3
  • 10-5 = 5
  • 17-10 = 7
  • 26-17 = 9
  • 37-26 = 11

Second differences are ...

  • 5 -3 = 2
  • 7 -5 = 2
  • 9 -7 = 2
  • 11 -9 = 2

The second differences are constant, so the sequence can be described by a second-degree polynomial.

We can write and solve three equations for the coefficients of the polynomial. Let's define the polynomial for the sequence as ...

  f(n) = an^2 + bn + c

Then the first three terms of the sequence are ...

  • f(1) = 2 = a·1^2 + b·1 + c
  • f(2) = 5 = a·2^2 +b·2 + c
  • f(3) = 10 = a·3^2 +b·3 +c

Subtracting the first equation from the other two gives ...

  3a +b = 3

  8a +2b = 8

Subtracting the first of these from half the second gives ...

  (4a +b) -(3a +b) = (4) -(3)

  a = 1 . . . . . simplify

Substituting into the first of the 2-term equations, we get ...

  3·1 +b = 3

  b = 0

And substituting the values for a and b into the equation for f(1), we have ...

  1·1 + 0 + c = 2

  c = 1

So, the formula for the sequence is ...

  f(n) = n^2 + 1

__

The 20th term is f(20):

  f(20) = 20^2 +1 = 401

_____

<em>Comment on the solution</em>

It looks like this matches the solution of the "worked example" on your problem page.

4 0
3 years ago
The general solution of 2 y ln(x)y' = (y^2 + 4)/x is
Sav [38]

Replace y' with \dfrac{\mathrm dy}{\mathrm dx} to see that this ODE is separable:

2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}

Integrate both sides; on the left, set u=y^2+4 so that \mathrm du=2y\,\mathrm dy; on the right, set v=\ln x so that \mathrm dv=\dfrac{\mathrm dx}x. Then

\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v

\implies\ln|u|=\ln|v|+C

\implies\ln(y^2+4)=\ln|\ln x|+C

\implies y^2+4=e^{\ln|\ln x|+C}

\implies y^2=C|\ln x|-4

\implies y=\pm\sqrt{C|\ln x|-4}

4 0
3 years ago
Simplify y2+4y–16y+3y2.
nadya68 [22]

Answer:

4y^2-12y

Step-by-step explanation:

y^2+4y-16y+3y^2

=y^2+3y^2+4y-16y

=4y^2+4y-16y

=4y^2-12y

6 0
3 years ago
Can someone help me please
Leviafan [203]

Answer:

(-2,-4) and (4,-6) are the plot points. I wasn't really sure about what your question was exactly so I hope this helps.

3 0
3 years ago
Can you guys help me pleaseeeeeeee ?
loris [4]
You will be choosing A
4 0
3 years ago
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