Sorry what question? I don’t see anything so I can’t help.
The base length of the triangle is 10 ft. and the height of the triangle is 20ft.
Step-by-step explanation:
Height = base + 10
Area = 100 square ft
Area of a triangle= (1/2) (b) (h)
100 = (1/2) (b) (b + 10)
200 = b(b) + 10b
b(b) + 10b - 200 = 0
b(b) + 20b - 10b - 200 = 0
b ( b + 20) -10(b + 20) = 0
(b-10) (b+20) =0
b = 10 (or) b = -20
Here b is the length and cannot be negative.
So, b = 10ft
h = b + 10
h = 10 + 10
h = 20 ft.
The base length of the triangle is 10 ft. and the height of the triangle is 20ft.
We have the equation:
We know two points and we will use them to calculate the parameters a and b.
The point (0,3) will let us know a, as b^0=1.
Now, we use the point (2, 108/25) to calcualte b:
![\begin{gathered} y=3\cdot b^x \\ \frac{108}{25}=3\cdot b^2 \\ 3\cdot b^2=\frac{108}{25} \\ b^2=\frac{108}{25\cdot3}=\frac{108}{3}\cdot\frac{1}{25}=\frac{36}{25} \\ b=\sqrt[]{\frac{36}{25}} \\ b=\frac{\sqrt[]{36}}{\sqrt[]{25}} \\ b=\frac{6}{5} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20y%3D3%5Ccdot%20b%5Ex%20%5C%5C%20%5Cfrac%7B108%7D%7B25%7D%3D3%5Ccdot%20b%5E2%20%5C%5C%203%5Ccdot%20b%5E2%3D%5Cfrac%7B108%7D%7B25%7D%20%5C%5C%20b%5E2%3D%5Cfrac%7B108%7D%7B25%5Ccdot3%7D%3D%5Cfrac%7B108%7D%7B3%7D%5Ccdot%5Cfrac%7B1%7D%7B25%7D%3D%5Cfrac%7B36%7D%7B25%7D%20%5C%5C%20b%3D%5Csqrt%5B%5D%7B%5Cfrac%7B36%7D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B%5Csqrt%5B%5D%7B36%7D%7D%7B%5Csqrt%5B%5D%7B25%7D%7D%20%5C%5C%20b%3D%5Cfrac%7B6%7D%7B5%7D%20%5Cend%7Bgathered%7D)
Then, we can write the equation as:
Answer:
(3,4)
Step-by-step explanation:
The system of equations is:
x+6y=27
7x-3y=9.
I looked up "metodo de igualacion". It is basically American for doing substitution.
However, the only difference is you are asked to solve both equations for a variable.
The first equation looks easy to solve for x. So I'm going to solve both equations for x.
x+6y=27
Subtract 6y on both sides:
x =-6y+27
7x-3y=9
Add 3y on both sides:
7x =3y+9
Divide both sides by 7:
x =3/7 y +9/7
So both equations are solved for x. You want to find when the x's are the same because you are looking for a common amongst the lines given.
So we have
-6y+27=3/7 y +9/7
I hate the fractions honestly so I'm going to multiply both sides by 7 so they will no longer be for now:
-42y+189=3y + 9
Now add 42y on both sides:
189=45y+9
Subtract 9 on both sides:
180=45y
Divide both sides by 45:
4=y
If 4=y, then y=4.
So now once we have obtain 4 for y, we will use one of the equations given along with it to find x. Just choose one. Choose the easier looking one to you.
I like the x=-6y+27 with y=4.
So replace y with giving you:
x=-6(4)+27
x=-24+27
x=3
So the solution is (x,y)=(3,4).
x=3 and y=4.
