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ratelena [41]
3 years ago
10

if a safety switch has a 1 in 10 chance of failing, how many switches would a company want to install in order to have only a 1

in million chance of them all failing at the same time
Mathematics
2 answers:
tatiyna3 years ago
8 0
10^-n=10^-6

So n=6

Thus they will want to install 6 switches...


Romashka-Z-Leto [24]3 years ago
7 0
Because every individual switch has a 1/10 chance of failing, two switches will have a (1/10)*(1/10) chance of failing.  Three switches will have a (1/10)*(1/10)*(1/10) chance of failing.  This pattern will continue.  Because ( \frac{1}{10} )^6 equals 1/1,000,000, 6 switches will give you a 1 in 1 million chance of all failing at the same time.
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