if a safety switch has a 1 in 10 chance of failing, how many switches would a company want to install in order to have only a 1
2 answers:
Because every individual switch has a 1/10 chance of failing, two switches will have a (1/10)*(1/10) chance of failing. Three switches will have a (1/10)*(1/10)*(1/10) chance of failing. This pattern will continue. Because 
equals 1/1,000,000, 6 switches will give you a 1 in 1 million chance of all failing at the same time.
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Multiply each of the numbers by a ten to a power that they both become whole numbers.
0.67 *
= 67
0.3 * = 30
Divide as usual.
67 / 30 = 2
So, the answer is 2 1/3.
0.67 *
0.3 *
Divide as usual.
67 / 30 = 2
So, the answer is 2 1/3.