26 because 5 gose in to 13 2 times and you have 3 left bring down the zero for 30 and 6 gose in to it evenly
Let's solve the inequality. Subtract 5 from both sides. The result will be
<span>x ≥ 5. This states, "x is equal to or greater than 5."
</span>
Plot 5 on the number line, using a dark solid dot. Then draw an arrow from that point to the right.
X^2-6x=13
(x-3)^2-9=13
(x-3)^2=22
(x-3)= +-sqrt22
x = sqrt22+3 or x = -sqrt22+3
Answer:
a) P (x is less than 11 minutes) = 0.55
P (x is more than 14 minutes) = 0.3
b) P (x is between 8 and 13 minutes) = 0.25
c) P(x < c) =0.8 is 0.05 x c = 0.8
Step-by-step explanation:
a) P (x is less than 11 minutes) = 11 x 0.05
= 0.55
P (x is more than 14 minutes) = 0.05 x (20 - 14)
= 0.05 x 6
= 0.3
b) P (x is between 8 and 13 minutes) = 0.05 x (13 -8)
= 0.05 x 5
= 0.25
c) P(x < c) =0.8
The area between 0 and c is 0.8
Hence,
0.05 x c = 0.8
B. First off , standard form of a 2nd degree equation is Ax^2 + Bx + C. So look at the coefficient of Ax^2 which is -2.
If positive, the parabola opens up and has a minimum.
If negative, the parabola opens down and has a maximum.
A. To find the vertex (in this case maximum),
Graph the equation -OR—
make a table. — OR—
Find the zeroes and find the middle x-value
-2x^2 - 4x + 6
-2(x^2 +2x - 3 = 0
-2 (x - 1) ( x + 3)=0
x - 1 = 0. x + 3 = 0
x = 1. x = -3. So halfway would be at (-1, __).
Sub in -1 into original equation -2x^2 -4x + 6 … -2(-1)^2 -4(-1) + 6 = -2 +4 +6 = 8
So the vertex is (-1,8)
