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Licemer1 [7]
3 years ago
5

A Penteria is a special (fictional) kind of bacteria such that, regardless of the original population in a collection, the popul

ation increases by $5$ every minute. Additionally, at the end of every hour, all but the initial ones die. If $137$ Penteria are alive after $506$ minutes, how many were there at the beginning?
Mathematics
1 answer:
Rashid [163]3 years ago
4 0
The answer is 23 because u have to multiply
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Can anyone find the x and y intercepts for this equation?
ASHA 777 [7]
<span><u>1/3x - 1/2y = 1</u>

At the 'x' intercept, y=0 , and the equation is    1/3 x = 1

Multiply each side by 3 :            <em>x = 3 </em> <== the x-intercept


At the 'y' intercept,  x=0, and the equation is  -1/2 y = 1

Multiply each side by  2 :            - y = 2

Multiply each side by  -1 :            <em> y = -2  </em>  <== the y-intercept
</span>
7 0
3 years ago
What is the exact volume of the cone?<br><br> H = 6 cm<br> R = 9 cm
faltersainse [42]

Answer:

508.68 or 508.7

Step-by-step explanation:

V=1/3(3.14)(9)^2(6)

(3.14)(81) x 6

(3.14)(486)

1/3(1526)

(divide by 3)= 508.68

6 0
3 years ago
What is the value of the expression below after it has been simplified completely? (2)(3)-(6)(4) A. –24 B. –18 C. 18 D. 24
AlexFokin [52]

Answer:

B

Step-by-step explanation:

2x3=6 and 6x4=24 so 6-24= -18

4 0
3 years ago
How much money is a 20% down payment on a $23,900 car?
vlada-n [284]

Answer:

$4,780

Step-by-step explanation:

20% x 23,900= 4,780

5 0
3 years ago
Read 2 more answers
How many extraneous solutions does the equation below have?
aev [14]

Answer:

A solution is said to be extraneous, if it is a zero of the equation, but it does not satisfy the equation,when substituted in the original equation,L.H.S≠R.H.S. 

The given equation consisting of  variable , m is

   \frac{2 m}{2 m+3} -\frac{2 m}{2 m-3}=1\\\\ 2 m[\frac{1}{2 m+3} -\frac{1}{2 m-3}]=1\\\\ 2 m\times \frac{[2 m-3 -2 m- 3]}{4m^2-9}=1\\\\ -6 \times 2 m=4 m^2 -9\\\\ 4 m^2 +1 2 m -9=0\\\\m=\frac{-12 \pm\sqrt{12^2-4 \times 4 \times (-9)}}{2\times 4}\\\\m=\frac{-12 \pm \sqrt {144+144}}{8}\\\\m=\frac{-12 \pm \sqrt {288}}{8}\\\\m=\frac{-12 \pm 12 \sqrt{2}}{8}\\\\m=\frac{3}{2}\times(-1 \pm \sqrt{2})

None of the two solution

m=\frac{3}{2}\times(-1 +\sqrt{2}) and , m=\frac{3}{2}\times(-1 -\sqrt{2}), is extraneous.

Here, L.H.S= R.H.S

Option A: 0→ extraneous

8 0
2 years ago
Read 2 more answers
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