If I were you, I would make the starting point (3,-6). From there, you will want to use the slope of -1/2 (go down 1 unit and to the right 2 units and draw a point)

4 0

3 years ago

Find the height of the building below by using your knowledge of trigonometry.

Lilit [14]

Answer:

50 $\sqrt{3}$

Step-by-step explanation:

The figure represents a 30-60-90 special triangle

in this special right triangle the measure of sides lengths is represented by

a, a $\sqrt{3}$ , and 2a

The side length that sees angle measure 30 is represented by a and here we see a = 50m

The height of the building, which sees angle measure 60, is equal to

50 $\sqrt{3}$

5 0

2 years ago

Which is equivalent to x^3 y^-7

PilotLPTM [1.2K]

For this case we must find an expression equivalent to:

$x ^ 3 * y ^ {- 7}$

By definition of power properties we have to meet:

$a ^ {-1} = \frac {1} {a ^ 1} = \frac {1} {a}$

Then, we can rewrite the expression as:

$x ^ 3 * \frac {1} {y ^ 7} =\\\frac {x ^ 3} {y ^ 7}$

Answer:

$\frac {x ^ 3} {y ^ 7}$

8 0

3 years ago