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1 year ago

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Inequalities definition

2 answers:

Kipish [7]1 year ago

7 0

Answer:

In Algebra, inequality is a Mathematical statement that shows the relation between two expressions using the inequality symbol. The expressions on both sides of an inequality sign are not equal. It means that the expression on the left-hand side should be greater than or less than the expression on the right-hand side or vice versa. If the relationship between two algebraic expressions is defined using the inequality symbols, then it is called literal inequalities. If two real numbers or the algebraic expressions are related by the symbols “>”, “<”, “≥”, “≤”, then the relation is called an inequality.

Black_prince [1.1K]1 year ago

6 0

Answer:

a inequality is a relation which makes a non-equal comparison between two numbers or other mathematical expressions. It is used most often to compare two numbers on the number line by their size.

Step-by-step explanation:

hope it helps :)

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The formula for the surface area of a cylinder with radius r and height h is at times twice the product of the

MrMuchimi

Answer:

<em> $2\pi \: rh + 2\pi {r}^{2} = 2(t \times {r}^{2} )$ </em>

Step-by-step explanation:

The TSA of the cylinder

$2\pi \: rh + 2\pi {r}^{2}$

In Mathematics, 'is' is =

Twice means 2( )

Product means ×

So we have

$2\pi \: rh + 2\pi {r}^{2} = 2(t \times {r}^{2} )$

as the answer.

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2 years ago

If your test increased by 14 points, what percent did you increase if there were 50 questions in total? show work

solmaris [256]

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3 years ago

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marta [7]

Answer:

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2 years ago

Classify the triangle with the given side lengths: 5, 9, 10

Volgvan

This can be a right triangle

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2 years ago

(Y+3)(y^2-3y+9)<br><br> A. Y^3+27<br> B. Y^3-27<br> C. Y^3-6y^2+27<br> D. Y^3+6y^2+27

KonstantinChe [14]

Answer:

A) y^3+27

Step-by-step explanation:

There are two ways of solving this problem:

1. Recognizing this as the factored form of the sum of perfect cubes

2. Distribute and add the like terms.

1. In order to distribute we must multiply y by y^2-3y+9, and then 3 by y^2-3y+9:

$(y+3)(y^2-3y+9)=y(y^2-3y+9)+3(y^2-3y+9)$

$y(y^2-3y+9)+3(y^2-3y+9)=y^3-3y^2+9y+3y^2-9y+27$

After we add the positive and negative 3y^2 and 9y, they will cancel out and be gone entirely:

$y^3-3y^2+9y+3y^2-9y+27=y^3+27$

2. You know how you can factor the difference of perfect squares?

As an example:

$a^2-b^2=(a+b)(a-b)$

Well, not many people know this but you can actually factor both the sum and difference of perfect cubes:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

$a^3-b^3=(a-b)(a^2+ab+b^2)$

Because we have these identities, we can easily establish here that we have the sum of perfect cubes, and that (y+3)(y^2-3y+9)= y^3+3^3 = y^3+27

6 0

2 years ago