2.) 3
3.) 3723
4.) 1512
5.)4692
6.)5525
7.) 760
8.) 696
Im confused as to what you are asking!
Answer: 
Step-by-step explanation:
For this exercise it is necessary to remember the following:
1) The Distributive Property states the following:
2) The multiplication of signs:
Knowing this, and having the following expression given in the exercise:
You can apply the Distributive property multiplying 
and 
, which are inside the parentheses, by 
.
So, you get the following result:
A standard deck of 52 cards has 4 suits (spades, clubs, hearts, and diamonds) with 13 different cards (ace, 2, 3, 4, 5, 6, 7, 8,
Inessa [10]
Answer:
P(a pair with matching cards in different suits) = 1/52
Step-by-step explanation:
We are told that there are 4 suites and each suit has 13 different cards. This is a total of 52 cards.
Thus;
Probability of selecting one card of a particular suit = 13/52 = 1/4
If we now want to select a matching card of another suit without replacing the first one, then, we now have; 52 - 13 = 39 cards. Now, there are only 3 matching cards of the 3 remaining suits that is same as the first card drawn.
Thus; probability = 3/39 = 1/13
Thus;
P(a pair with matching cards in different suits) = 1/4 × 1/13
P(a pair with matching cards in different suits) = 1/52
Answer:
Step-by-step explanation:
In general, probably can be found as n(E)/n(S), where n(E) is the number of favorable outcomes, and n(S) is the number of total outcomes.
n(S) is the number of ways any 9 students can by picked from the audience, which is 9/140.
n(E) is the probability of picking four students from our school and five students from another school. This is (4/30)*(5/110) = 9/3300 =3/1100
n(E)/n(S) = (3/1100) / (9/140) = (3/1100) * (140/9) = 14/330
