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sineoko [7]
2 years ago
9

What’s y’all’s favorite fruit ( ˘ ³˘)♥︎

Mathematics
1 answer:
Bond [772]2 years ago
8 0
Strawberries are my favorite fruit
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Just need help with this question, would like an explanation as to how you got the answer so I can know for further assignments!
MrRa [10]

Answer:

p=0, p=.25

Step-by-step explanation:

p*(4p-1)=0

p=0. when the product of factors equals zero at least one factor is zero

4p-1=0

p=1/4 or .25

7 0
2 years ago
Read 2 more answers
Jacob bought a new circular saw . Then he bought 8 different blades for it. Each blade cost $23 . How much did Jacob spent on al
bixtya [17]
So if each blade cost $23 you could add 23 8 times.
23+23+23+23+23+23+23+23= 184
or if you can do multiplication it could be
23x8=184
In total Jacob spent $184
4 0
3 years ago
In 2011, the average annual premium for GEICO insurance policy owners in California dropped from $ 1187 to $ 1060. Find the perc
Allushta [10]
The answer is going to be 127% Hopes this helps :)
6 0
3 years ago
Which of the following could be the side lengths of a right triangle
ASHA 777 [7]

The lengths of a right triangle's three sides can be expressed as 24, 32, and 40.

Let's work our way through the solution. According to the right triangle formula, a triangle's hypotenuse square equals the sum of its base square and its altitude square.

How to determine a right triangle's sides?

If leg an is absent, change the equation to its form when leg an is present on one side and compute the square root: a = (c2 - b2).

Leg b must be unknown otherwise. b = √(c² - a²)

The equation for hypotenuse c is: c = (a2 + b2)

to learn more about right triangle's sides refer to:

brainly.com/question/3223211

#SPJ13

7 0
1 year ago
Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
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