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Ber [7]
3 years ago
15

If a line segment contains one endpoint at (2,3) and has a midpoint of (-2,6) what is the second endpoint of the line segment

Mathematics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

Step-by-step explanation:

The coordinates of the midpoint M are the average of the coordinates of the two endpoints:

M_x = \dfrac{2+x}{2},\quad M_y = \dfrac{3+y}{2}

Plug the known coordinates of the midpoint:

-2 = \dfrac{2+x}{2},\quad 6 = \dfrac{3+y}{2}

Solve for x and y:

-4 = 2+x,\quad 12 = 3+y

x=-6,\quad y = 9

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WILL MARK BRAINLIEST
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<h3>Refer to the diagram below</h3>
  1. Draw one smaller circle inside another larger circle. Make sure the circle's edges do not touch in any way. Based on this diagram, you can see that any tangent of the smaller circle cannot possibly intersect the larger circle at exactly one location (hence that inner circle tangent cannot be a tangent to the larger circle). So that's why there are no common tangents in this situation.
  2. Start with the drawing made in problem 1. Move the smaller circle so that it's now touching the larger circle at exactly one point. Make sure the smaller circle is completely inside the larger one. They both share a common point of tangency and therefore share a common single tangent line.
  3. Start with the drawing made for problem 2. Move the smaller circle so that it's partially outside the larger circle. This will allow for two different common tangents to form.
  4. Start with the drawing made for problem 3. Move the smaller circle so that it's completely outside the larger circle, but have the circles touch at exactly one point. This will allow for an internal common tangent plus two extra external common tangents.
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Refer to the diagram below for examples of what I mean.

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