2 years ago

Please help me with expression

Mathematics

1 answer:

steposvetlana [31]2 years ago

4 0

For the first one its (A) For the 2nd its (C) For the 3rd its (B)

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2/3 (6y - 4) = - 4y <br>

Nookie1986 [14]

Answer:

y = 1/3

Step-by-step explanation:

2/3 (6y - 4) = - 4y

2(6y-4)/3 = -4y

2(6y-4) = (-3)(4y)

y = 1/3

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2 years ago

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Find the next two terms in the pattern 100,98,94,88,80…

olga_2 [115]

Answer:

its 70 and 58

Step-by-step explanation:

The pattern: -2, -4, -6, -8, -10, -12...

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The candy of a lolipop is in the shape of a sphere with a diameter of 4 cm. The

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So so so so 0.5cm? Like

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2 years ago

If the points on a graph of a linear function are (-2,10 (0,4) (2,-2) and (4,8) what is the y-intercept

MatroZZZ [7]

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i think 5

Step-by-step explanation:

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What is the 6th term of the geometric sequence where a1 = -4096 and a4 = 64?

Akimi4 [234]

$\bf \begin{array}{llccll}
term&value\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
a_1&-4096\\
a_2&-4096r\\
a_3&-4096rr\\
a_4&-4096rrr\\
&-4096r^3\\
&64
\end{array}\implies -4096r^3=64
\\\\\\
r^3=\cfrac{64}{-4096}\implies r^3=-\cfrac{1}{64}\implies r=\sqrt[3]{-\cfrac{1}{64}}
\\\\\\
r=\cfrac{\sqrt[3]{-1}}{\sqrt[3]{64}}\implies \boxed{r=\cfrac{-1}{4}}\\\\
-------------------------------$

$\bf n^{th}\textit{ term of a geometric sequence}\\\\
a_n=a_1\cdot r^{n-1}\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
r=\textit{common ratio}\\
----------\\
r=-\frac{1}{4}\\
a_1=-4096\\
n=6
\end{cases}
\\\\\\
a_6=-4096\left( -\frac{1}{4} \right)^{6-1}\implies a_6=-4^6\left( -\frac{1}{4} \right)^5$

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2 years ago

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