The additional operation which needed to make the expression equivalent to given expression is 
. Thus the option 3 is the correct option.
<h3>What is equivalent expression?</h3>
Equivalent expression are the expression whose result is equal to the original expression, but the way of representation is different.
Given information-
The equation given in the problem is,
Let the equation is equation number 1.
This expression is to convert in the expression, which is,
Let the above equation is equation number 2.
Let the additional operation which needed to make the expression equivalent to given expression is 
.
As the addition of and equation 1 is equal to the equation 2. Therefore,
Solve the equation as,
Hence, the additional operation which needed to make the expression equivalent to given expression is . Thus the option 3 is the correct option.
Learn more about the equivalent expression here;
brainly.com/question/2972832
Answer:
<h2>
234</h2><h2>
</h2>
Step-by-step explanation:
surface area = 2( LW + LH + WH)
where L = Length = 9
W = Width = 2
H = Height = 9
<u>plugin values into the formula:</u>
surface area = 2 ( LW + LH + WH)
= 2 ( 9*2 + 9*9 + 2*9 )
= 2 ( 18 + 81 + 18 )
= 2 (117)
= 234
<h3>
Answer: 140625 </h3>
======================================================
Explanation:
Replace every copy of "w" with "x"
So the function we graph is y = (1500-2x)*x/2
I used GeoGebra to make the graph below. Note the scale on the xy axis. In this case, x is incrementing by 100 while y is incrementing by 50,000. The scale is important so you have a good viewing window. You don't have to have this scale exactly, but something close to it should do the trick. Without the proper scale, you probably won't see the curve at all. You may see a straight line instead, or it may appear completely blank.
You can use Desmos to make the graph. Just keep in mind the scale of course.
Once you have the graph set up, use the max feature of your graphing calculator or graphing software to locate the vertex point. In GeoGebra, the function I used is "Max". I typed in Max(f, 0, 800) where f is the function mentioned earlier. With Desmos, you simply need to click on the curve itself to have the max point show up. Click on the vertex point to have the coordinates listed.
The max point is located at A = (375, 140625) as shown in the diagram below. The x coordinate is the value of "w" that we replaced earlier. So a width of w = 375 feet corresponds to the max area of 140625 square feet.
Side note: later on in your math career, you have the option to use calculus to solve a problem like this. Though for now, we can rely on a graphing calculator to get the job done quickly.
240 is the answer to this problem
Answer: 29 feet (deepest) at 6 am
21 feet (shallowest) at Midnight & Noon
<u>Step-by-step explanation:</u>
y = -4 cos (π/6)t +25
Amplitude (A) = 4
-A means it is a reflection over the x-axis (starts at minimum)<em> </em>
Period = 2π/B → Period = 12
Phase shift = C/B → Phase Shift = 0
Midline (D) = 25
Midline (D) ± Amplitude (A) = Max & Min
Max: 25 + 4 = 29
Min: 25 - 4 = 21
Change the coordinates of y = cos (x) as follows:
- x-value: Add C then divide by B
- y-value: Multiply by A then add D
Note that the equation shows: A = -4, B = π/6, C = 0, D = 25
