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Strike441 [17]
3 years ago
9

Suppose you are traveling straight from Los Angeles, California to Albuquerque, New Mexico, stopping overnight in Flagstaff, Ari

zona. The distance from L.A. to Albuquerque is 810 miles, and the road connecting the three cities is a straight line. If the distance from L.A. to Flagstaff is 120 miles greater than the distance from Flagstaff to Albuquerque, how far is L.A. from Flagstaff, and how far is Flagstaff from Albuquerque? A. L.A. to Flagstaff, 460 miles; Flagstaff to Albuquerque, 350 miles B. L.A. to Flagstaff, 463 miles; Flagstaff to Albuquerque, 347 miles C. L.A. to Flagstaff, 464 miles; Flagstaff to Albuquerque, 346 miles D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles
Mathematics
1 answer:
Roman55 [17]3 years ago
3 0
<span>D. L.A. to Flagstaff, 465 miles; Flagstaff to Albuquerque, 345 miles

The answer above is correct.

810 - 120 = 690 ; 690 / 2 = 345 mi   ( Flagstaff to Albuquerque )

810 - 345 = 465 mi   ( L.A. to Flagstaff )


</span>
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Please helppp me!!!!!
Scrat [10]

Answer:

Step 2 contains error in the given problem.

Step-by-step explanation:

Given expression is:

\frac{1}{2}x-3=\frac{1}{3}x+6

Step 1: identifying the LCM.

The LCM identified is 6.

This step is correct.

In the next step, we multiply the LCM with each term of the equation.

Step 2:

\frac{6}{1}(\frac{1}{2}x) -3 =\frac{6}{1}(\frac{1}{3}x)+6

However,

In the given solution, the LCM is not multiplied with each term.

Hence,

Step 2 contains error in the given problem.

7 0
2 years ago
Using the Addition Method, find the value of x in the
allochka39001 [22]

Step-by-step explanation:

3x+2y=2------------1

-3x+5y=5-----------2

adding 1 and 2 we get

7y=7

y=1

and from (1),we get

3x+2×1=2

3x=0

x=0 is the required value of x.

8 0
3 years ago
Consider the equation below. f(x) = 2x3 + 3x2 − 336x (a) Find the interval on which f is increasing. (Enter your answer in inter
Vaselesa [24]

We have been given a function f(x)=2x^3+3x^2-336x. We are asked to find the interval on which function is increasing and decreasing.

(a). First of all, we will find the critical points of function by equating derivative with 0.

f'(x)=2(3)x^{2}+3(2)x^1-336

f'(x)=6x^{2}+6x-336

6x^{2}+6x-336=0

x^{2}+x-56=0

x^{2}+8x-7x-56=0

(x+8)-7(x+8)=0

(x+8)(x-7)=0

x=-8,x=7

So x=-8,7 are critical points and these will divide our function in 3 intervals (-\infty,-8)U(-8,7)U(7,\infty).

Now we will find derivative over each interval as:

f'(x)=(x+8)(x-7)

f'(-9)=(-9+8)(-9-7)=(-1)(-16)=16

Since f'(9)>0, therefore, function is increasing on interval (-\infty,-8).

f'(x)=(x+8)(x-7)

f'(1)=(1+8)(1-7)=(9)(-6)=-54

Since f'(1), therefore, function is decreasing on interval (-8,7).

Let us check for the derivative at x=8.

f'(x)=(x+8)(x-7)

f'(8)=(8+8)(8-7)=(16)(1)=16

Since f'(8)>0, therefore, function is increasing on interval (7,\infty).

(b) Since x=-8,7 are critical points, so these will be either a maximum or minimum.

Let us find values of f(x) on these two points.

f(-8)=2(-8)^3+3(-8)^2-336(-8)

f(-8)=1856

f(7)=2(7)^3+3(7)^2-336(7)

f(7)=-1519

Therefore, (-8,1856) is a local maximum and (7,-1519) is a local minimum.

(c) To find inflection points, we need to check where 2nd derivative is equal to 0.

Let us find 2nd derivative.

f''(x)=6(2)x^{1}+6

f''(x)=12x+6

12x+6=0

12x=-6

\frac{12x}{12}=-\frac{6}{12}

x=-\frac{1}{2}

Therefore, x=-\frac{1}{2} is an inflection point of given function.

3 0
3 years ago
3 cans of soup cost $0.99 how much do five cans cost
IrinaVladis [17]
$1.65 THAT IS CLEARLY THE ANSWER BEACEUSE EACH CAN IS 33 CENTS SO 5 CANS IS 33 * 5= 1.65
4 0
2 years ago
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What is the GCF of 81 and 36?<br> What is the LCM of 4 and 9?
Mila [183]
The question "What is the LCM and GCF of 36 and 81?" can be split into two questions: "What is the LCM of 36 and 81?" and "What is the GCF of 36 and 81?"

In the question "What is the LCM and GCF of 36 and 81?", LCM is the abbreviation of Least Common Multiple and GCF is the abbreviation of Greatest Common Factor.

To find the LCM, we first list the multiples of 36 and 81 and then we find the smallest multiple they have in common. To find the multiples of any number, you simply multiply the number by 1, then by 2, then by 3 and so on. Here is the beginning list of multiples of 36 and 81:

Multiples of 36: 36, 72, 108, 144, 180, 216, etc.

Multiples of 81: 81, 162, 243, 324, 405, 486, etc.

The least multiple on the two lists that they have in common is the LCM of 36 and 81. Therefore, the LCM of 36 and 81 is 324.
4 0
3 years ago
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