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Basile [38]
3 years ago
11

How to solve? I basically want to know the first step..

Mathematics
2 answers:
Ratling [72]3 years ago
8 0
In the equation x-y = 5 subtract x from both sides , and then divide by -y. so at the ned you will get what y equals to and plug that into your equation
2x-2y = 10.

Let me know if this is helpful :) <span />
inessss [21]3 years ago
5 0
You have to get x alone and then do the rest of the steps
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Classify each of the following numbers as real, whole, integer, rational or irrational. Some numbers will have more than one cla
Colt1911 [192]
Answer:
1). -98 (integer, real number, rational)
2). 1.98 (real, rational)
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3 0
3 years ago
PLEASE ANSWER ASAP!! WILL GIVE 50 POINTS! AND BRAINLIST!
levacccp [35]

\frac{3}{5}  -  \frac{1}{4}  =  \frac{7}{20}
then
\frac{7}{20}  \div  \frac{7}{10}  =  \frac{1}{2}
4 0
3 years ago
A company’s board of directors wants to form a committee of 3 of its members. There are 4 members to choose from. How many diffe
Ugo [173]

Answer:

4

Step-by-step explanation:

There are 4 board members and 3 committee members. You can solve this using combinations:

4C3 = 4!/(3!(4-3)!) = 4!/(3!1!) = 4

You can also solve this by recognizing that since there is one fewer committee spot than there are board members, there will be one possible committee excluding each of the 4 board members.

4 0
3 years ago
2(x + 3) = x - 4 <br>And <br>4(5x-2)=2(9x+3)<br>​
weqwewe [10]

2x+6 - х -4

2x - x = - 4 - 6

x=-10

20x - 8 = 18x +6

20x - 18x = 6 +8

2x = 14

x=7

4 0
3 years ago
what is the quotient 5-x/x^2 3x-4 divided by x^2-2x-15/x^2 5x 4 in simplifed form state any restrictions on the varible
zheka24 [161]

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Given that equation:

\frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4}

=\frac{5-x}{(x+4)(x-1)} /\frac{(x-5)(x+3)}{(x+4)(x+1)} \\\\=\frac{5-x}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\\frac{-(x-5)}{(x+4)(x-1)} * \frac{(x+4)(x+1)}{(x-5)(x+3)}\\\\=\frac{-(x+1)}{(x-1)(x+3)}

The quotient when \frac{5-x}{x^2+3x-4} /\frac{x^2-2x - 15}{x^2+5x+4} in simplified form is \frac{-(x+1)}{(x-1)(x+3)}

Find out more on equation at: brainly.com/question/2972832

#SPJ1

8 0
2 years ago
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