The perimeter of the equilateral triangle is 3s and s=4x so the perimeter is:
12x
And we are told that the perimeter of the square is the same. And that perimeter is 4s where s=(x+6) so that perimeter is equal to
4x+24, and again, we are told that these two values are equal so we can solve for x...
12x=4x+24
8x=24
x=3 and if x=3 then the side length is (x+6)=9
So the area of the square is always A=s^2 and s=9 thus:
A=9^2
A=81 u^2
Answer:
x=2 and y=−6
sorry this is pretty long, I did not know if you needed the steps or not
Step-by-step explanation:
−2y−10=x;−10x−y=−14
Solve−2y−10=x for x
−2y−10=x
−2y−10+−x=x+−x
−x−2y−10=0
−x−2y−10+2y=0+2y
−x−10=2y
−x−10+10=2y+10
−x=2y+10
-x/-1=2y+10/-1
x=−2y−10
Substitute−2y−10 for x in−10x−y=−14
−10x−y=−14
−10(−2y−10)−y=−14
19y+100=−14
19y+100+−100=−14+−100
19y=−114
19y/19=-114/19
y=-6
Substitute−6 for y in x=−2y−10
x=−2y−10
x=(−2)(−6)−10
x= 2
x=2 and y=−6
Answer:
Linear
Step-by-step explanation:
The numbers add by 4 it’s not scrambled
Answer:
6,561
Step-by-step explanation:
(-9)^4 = -9*-9*-9*-9= 6,561
