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3 years ago

How do you solve 3 1/2- 2 2/5

1 answer:

5 0

You would first have to find common denominators for the fractions. In this case it would be 10. So your new equation would be 3 5/10 - 2 4/10. Once you do this you can then subtract and solve getting the answer of 1 1/10

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It's -52 degrees F in Antarctica in the morning how many degrees must the temperature rise to reach 0 degrees F?

cluponka [151]

52 degrees f........

7 0

3 years ago

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10x + 8 = 3(x - 2)<br> 10x + 8 = 3x

lisabon 2012 [21]

Answer:

1) -2

2) 8/7

Step-by-step explanation:

1) 10x+8=3(x-2)

10x+8=3x-6

10x-3x=-6-8

7x=-14

x=-2

2) 10x+8=3x

10x-3x=8

7x=8

x=8/7

Hope it helps

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3 years ago

I am 1,000 times as big as a gram what am i

LiRa [457]

Answer:

One Kilogram

Step-by-step explanation:

1kg = 1000g

8 0

2 years ago

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1. One day at the farmer's market, a customer

lesya692 [45]

Answer:

She will get back $16.49

Explanation:

3.25+0.26=$3.51

$20-$3.51=$16.49

8 0

3 years ago

Water is drained out of tank, shaped as an inverted right circular cone that has a radius of 4cm and a height of 16cm, at the ra

bearhunter [10]

Answer:

$\frac{dh}{dt}=-\frac{1}{2\pi}cm/min$

Step-by-step explanation:

From similar triangles, see diagram in attachment

$\frac{r}{4}=\frac{h}{16}$

We solve for $r$ to obtain,

$r=\frac{h}{4}$

The formula for calculating the volume of a cone is

$V=\frac{1}{3}\pi r^2h$

We substitute the value of $r=\frac{h}{4}$ to obtain,

$V=\frac{1}{3}\pi (\frac{h}{4})^2h$

This implies that,

$V=\frac{1}{48}\pi h^3$

We now differentiate both sides with respect to $t$ to get,

$\frac{dV}{dt}=\frac{\pi}{16}h^2 \frac{dh}{dt}$

We were given that water is drained out of the tank at a rate of $2cm^3/min$

This implies that $\frac{dV}{dt}=-2cm^3/min$ .

Since we want to determine the rate at which the depth of the water is changing at the instance when the water in the tank is 8cm deep, it means $h=8cm$ .

We substitute this values to obtain,

$-2=\frac{\pi}{16}(8)^2 \frac{dh}{dt}$

$\Rightarrow -2=4\pi \frac{dh}{dt}$

$\Rightarrow -1=2\pi \frac{dh}{dt}$

$\frac{dh}{dt}=-\frac{1}{2\pi}$

3 0

4 years ago

Read 2 more answers