Answer:
Advance tickets=$25
Same-day tickets=$15
Step-by-step explanation:
Complete question below:
Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $ 40. For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1075 . What was the price of each kind of ticket?
Let
advance tickets=x
Same-day tickets=y
Combined cost of advance and same-day tickets=$40
It means,
x+y=40 Equ (1)
25 advance tickets and 30 same-day tickets=$1075
It means,
25x+30y=1075 Equ(2)
From (1)
x+y=40
x=40-y
Substitute x=40-y into (2)
25x+30y=1075
25(40-y)+30y=1075
1000-25y+30y=1075
5y=1075-1000
5y=75
Divide both sides by 5
5y/5=75/5
y=15
Recall,
x+y=40
x+15=40
x=40-15
=25
x=25
Advance tickets=$25
Same-day tickets=$15
Check
25x+30y=1075
25(25)+30(15)=1075
625+450=1075
1075=1075
First, multiply 3.5 by 20 and 2 by 20 to get the real width and length of the room(That would be 70 in. long and 40 in. wide). Then, change that into feet (Which would be 5.8 ft. long and 3.3 ft. wide). Lastly multiply the length by the width. The answer would then be 19.14.
Answer:
11k +12
Step-by-step explanation:
8k + 4 and 3k + 8
Combine like terms
8k + 4 + 3k + 8
8k+3k + 4+8
11k +12
If they already have $175, they need $250 more dollars. At $8 a water bottle, they would need to sell at least 32 more bottles.
