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stiv31 [10]
3 years ago
14

What is the length of BC? Round to the nearest tenth.

Mathematics
1 answer:
vredina [299]3 years ago
3 0

Answer:

BC ≈ 20.5 in

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos35° = \frac{adjacent}{hypotenuse} = \frac{BC}{AB} = \frac{BC}{25} ( multiply both sides by 25 )

25 × cos35° = BC , thus

BC ≈ 20.5 in ( to the nearest tenth )

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Brad bought 70.030 m of chain to make necklaces. He used 0.667 m of the chain to make one necklace.
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3 years ago
Please help and show work ​
san4es73 [151]

Step-by-step explanation:

Since PT = 2PM and AR = 2AD,

The midsegment MD must be the average of PA and TR:

Therefore we have

2(20x + 4) = 10 + (34x + 16)

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Hence length of MD

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8 0
3 years ago
HELP ASAP
Sindrei [870]

Answer:

median = 27

range = 29

mode = 32

maximum value = 41

interquartile range = 21

minimum = 12

upper quartile = 35

mean = 25

lower quartile = 14

Step-by-step explanation:

hope i helped

8 0
3 years ago
❗️❗️❗️Find the length of side x in simplest radical form with a rational denominator.❗️❗️❗️
harkovskaia [24]

Answer:

3

Step-by-step explanation:

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x=\sqrt{3} \cdot \sqrt{3}= \\\\\sqrt{3}^2= \\\\3

Hope this helps!

6 0
3 years ago
Read 2 more answers
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