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Anni [7]
3 years ago
13

What is the value for f(x)=4^2x-100 when x=2

Mathematics
2 answers:
11111nata11111 [884]3 years ago
4 0

Answer: f(2)=156

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

1. You have the following function:

f(x)=4^{2x}-100

2. Then, you must substitute x=2 into the function given in the exercise. Therefore, you have the following result:

f(2)=4^{2*2}-100\\f(2)=4^{4}-100\\f(2)=156

Papessa [141]3 years ago
3 0

Answer:

The value of f(2) = 156

Step-by-step explanation:

The given expression is  f(x)=4^2x-100

<u>To find f(2)</u>

when x=2  means we have to find the value of f(2)

Substituting the value of x as 2

f(x)=4^2x-100

f(2) = 4^(2*2) - 100 (Substitute the value of  x = 2)

f(2) = 4^4 - 100

f(2) = 4*4*4*4 - 100

f(2) = 256 - 100

f(2) = 156

Therefore the correct answer is  f(2) = 156

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