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lana [24]
3 years ago
7

Simplify: 3a + 2b - 8a + b

Mathematics
2 answers:
kupik [55]3 years ago
7 0

Answer:

-5a+3b

Step-by-step explanation:

3a + 2b - 8a + b

3a-8a= -5a

2b+b = 3b (Because b = 1b)

so answer will be -5a+3b

dezoksy [38]3 years ago
5 0
-5a+3b should be the answer simplified
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For each sequence find the first 4 terms and the 10th term
jolli1 [7]

Answer:For these, n is equal to the term you want. So you substitute the number in for whichever term you want. This means:

a) 1 (1st term) + 5 = 6

2 (2nd term) + 5 = 7

3 (3rd term) + 5 = 8

4 (4th term) + 5 = 9

10 (10th term) + 5 = 15

And so on for b (not going to keep writing the term, I’m sure you get that by now.

b) 2(1) - 1 = (2x1) - 1 = 1

2(2) - 1 = (2x2) - 1 = 3

2(3) - 1 = (2x3) - 1 = 5

2(4) - 1 = (2x4) - 1 = 7

2(10) - 1 = (2x10) - 1 = 19

Hope this helps :)

4 0
3 years ago
Bob Farrell works for a company that manufactures small appliances. Bob is paid $2.00 for each toaster, $4.60 for each microwave
Amiraneli [1.4K]

Answer:

$461.85

Step-by-step explanation:

Multiply 54x2,  36x4.60,  1.55x75

This comes out to 180, 165.6, and 116.25

Add them all together, and you get 461.85

That's the total amount that he makes weekly

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2 years ago
Write the equation of the line that passes through (2,4) and has a slope of -1 in point-slope from
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Find the rational zeros of the polynomial function, f(x)= 4x^3-8x^2-19x-7
Dima020 [189]

Answer:

The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  

Step-by-step explanation:

Given polynomial as :

f(x) = 4 x³ - 8 x² - 19 x - 7

Now the ration zero can be find as

\dfrac{\textrm factor of P}{\textrm factor Q} ,

where P is the constant term

And Q is the coefficient of the highest polynomial

So, From given polynomial ,  P = -7 , Q = 4

Now , \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q}

I.e  \dfrac{\textrm factor of \pm P}{\textrm factor of \pm Q} = \frac{\pm 7 , \pm 1}{\pm 4 ,\pm 2,\pm 1 }

Or, The rational zero are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1

Hence The rational zero of the polynomial are \pm \frac{7}{4}, \pm \frac{1}{4},\pm \frac{7}{2},\pm \frac{1}{2},\pm 7,\pm 1  .  Answer

7 0
3 years ago
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