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Varvara68 [4.7K]
4 years ago
11

The scores of eight grade students in a math test are normally distributed with a mean of 57.5 and a standard deviation of 6.5.

From this data, we can conclude that 68% of the students recieved scores between
a)34 and 64
b)34 and 68
c)51 and 64
d)51 and 68
Mathematics
1 answer:
rewona [7]4 years ago
8 0
Work out the z scores  for   51  and 54 
z1 = (51 - 57.5) / 6.5 = -1
z2 = (64  - 57.5)/6.5 = 1
from tables of normal distribution this value os 3413 + 3413  = 68.26%


so the answer is  c
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3 years ago
Confession under the radical in the quadratic formula that indicates the nature of the solutions real or complex rational or irr
spin [16.1K]

Answer:

discriminant

Step-by-step explanation:

Discriminant is the expression under the radical in a quadratic equation formula that indicates the nature of the solutions real or complex, rational or irrational , single or double root in other words

A discriminant can be said to be used to indicate the nature of the result that a quadratic equation when solved will yield and this can be : rational or irrational , complex or real, single or double roots. and it also indicates by how many  it would be  

3 0
3 years ago
Hannah has to make 25 gallons of punch for a potluck. The punch is made of soda and fruit drink. The cost of the soda is $1.79 p
Rus_ich [418]

Answer:

Hannah needs 10 gallons of soda and 15 gallons of fruit drink

Step-by-step explanation:

Let

x -----> the number of gallons of soda needed

y ----> the number of gallons of fruit drink needed

we know that

x+y=25 -----> equation A

1.79x+2.49y=2.21(25)

1.79x+2.49y=55.25 -----> equation B

Solve the system by graphing

Remember that the solution of the system of equations is the intersection point both graphs

The solution is the point (10,15)

see the attached figure

therefore

Hannah needs 10 gallons of soda and 15 gallons of fruit drink

3 0
3 years ago
Please help me if you can
Mrrafil [7]

Answer:

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4 0
3 years ago
Clarkson University surveyed alumni to learn more about what they think of Clarkson. One part of the survey asked respondents to
erastova [34]

Answer:

(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

Step-by-step explanation:

Let's denote the events as follows:

<em>A</em> = Fell short of expectations

<em>B</em> = Met expectations

<em>C</em> = Surpassed expectations

<em>N</em> = no response

<u>Given:</u>

P (N) = 0.04

P (A) = 0.26

P (B) = 0.65

(a)

Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:

P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05

Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.

(b)

The response of all individuals are independent.

Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

P(B\cup C) = P(B)+P(C)-P(B\cap C)\\=P(B)+P(C)-P(B)\times P(C)\\= 0.65 + 0.05 - (0.65\times0.05)\\=0.6675\\\approx0.67

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.

5 0
4 years ago
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