Do you need all of them answered? Is that what it is aking?? It is not very clear.
Answer:
discriminant
Step-by-step explanation:
Discriminant is the expression under the radical in a quadratic equation formula that indicates the nature of the solutions real or complex, rational or irrational , single or double root in other words
A discriminant can be said to be used to indicate the nature of the result that a quadratic equation when solved will yield and this can be : rational or irrational , complex or real, single or double roots. and it also indicates by how many it would be
Answer:
Hannah needs 10 gallons of soda and 15 gallons of fruit drink
Step-by-step explanation:
Let
x -----> the number of gallons of soda needed
y ----> the number of gallons of fruit drink needed
we know that
-----> equation A
-----> equation B
Solve the system by graphing
Remember that the solution of the system of equations is the intersection point both graphs
The solution is the point (10,15)
see the attached figure
therefore
Hannah needs 10 gallons of soda and 15 gallons of fruit drink
Answer:
(a) The probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b) The probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.
Step-by-step explanation:
Let's denote the events as follows:
<em>A</em> = Fell short of expectations
<em>B</em> = Met expectations
<em>C</em> = Surpassed expectations
<em>N</em> = no response
<u>Given:</u>
P (N) = 0.04
P (A) = 0.26
P (B) = 0.65
(a)
Compute the probability that a randomly selected alumnus would say their experience surpassed expectations as follows:
![P(C) = 1 - [P(A) + P(B) + P(N)]\\= 1 - [0.26 + 0.65 + 0.04]\\= 1 - 0.95\\= 0.05](https://tex.z-dn.net/?f=P%28C%29%20%3D%201%20-%20%5BP%28A%29%20%2B%20P%28B%29%20%2B%20P%28N%29%5D%5C%5C%3D%201%20-%20%5B0.26%20%2B%200.65%20%2B%200.04%5D%5C%5C%3D%201%20-%200.95%5C%5C%3D%200.05)
Thus, the probability that a randomly selected alumnus would say their experience surpassed expectations is 0.05.
(b)
The response of all individuals are independent.
Compute the probability that a randomly selected alumnus would say their experience met or surpassed expectations as follows:

Thus, the probability that a randomly selected alumnus would say their experience met or surpassed expectations is 0.67.