Answer:
10kg?
Step-by-step explanation:
Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
Remark
One of the things you need to do is learn to read phrase by phrase.
What is the quotient of a number and 7? That meas you have a number, x, and it is divided by 7. What you do that the answer you get is the quotient.
x/7 is what you know so for. Now the first part says you take 12 away from that.
x/7 - 12 is what you have after doing that.
The result you get is - 2
x/7 - 12 = - 2 Add 12 to both sides
x/7 - 12 + 12 = - 2 + 12
x/7 = 10 Now multiply by 7
x = 10 *7
x = 70 <<< Answer the number is 70
If they drove a total of 5,300 miles in 2 days, and on the second day they drove 10 more miles then the 1st day.
5,300 ÷ 2 = 2,650
they drove 10 miles less on the first day
2,650 - 10 = 2,640
They drove 2,640 miles on the first day.
Hope this helps. :)
<h3>They are 268 miles far apart after 4 hours</h3>
<h3>Further explanation</h3>
Acceleration is rate of change of velocity.
<em>a = acceleration ( m/s² )</em>
<em>v = final velocity ( m/s )</em>
<em>u = initial velocity ( m/s )</em>
<em>t = time taken ( s )</em>
<em>d = distance ( m )</em>
Let us now tackle the problem !
<u>Given :</u>
v₁ = 30 mph due east
v₂ = 60 mph due south
t = 4 hours
<u>Unknown :</u>
displacement = d = ?
<u>Solution :</u>
<h2>Conclusion :</h2><h3>They are 268 miles far apart after 4 hours</h3>
<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate
