Answer:
Erik's average speed exceeds the speed limit by 6.91 miles per hour.
Step-by-step explanation:
Let suppose that Erik travels at constant speed. Hence, the speed (
), measured in miles per hour, is determined by following equation of motion:
(1)
Where:
- Distance, measured in miles.
- Time, measured in hours.
Please notice that a hour equals 60 minutes. If we know that
and
, then the speed of Erik is:


Which is 6.91 miles per hour above the speed limit.
Answer:
Step-by-step explanation:
x^2+20=2x move 2x to the left
x^2-2x+20=0
Quadratic formula =
x=1± i√19
Answer:
I´m not a Mr. Beast fan but the answer is 4. 4*12 (which is the sum of 7 and 5) = 48
The equation is (7+5)x=48
Hey there! :)
Answer:
y = 5x + 10
Step-by-step explanation:
From the information given, we can derive the points (-2, 0) and (0, 10). Find the slope using the slope formula:

Plug in the points:

Simplify:

m = 5.
The equation in slope-intercept form is y = mx + b. We were already given the b value, or y-intercept as y = 10. Therefore:
y = 5x + 10 is the equation written in slope-intercept form.
The answer: m∡BCD = 130° .
_____________________________________
Explanation:
______________________________
m∡BCD = 9x - 5 = our answer.
_____________________________
Note: (9x - 5) + (m∡C IN Δ ACB)= 180 ;
____________________________
Reason: all angles on straight line add up to 180.
___________________________
Note: In Δ ACB; m∡A + m∡B + m∡c = 180.
_________________________________________
Reason: All three angles in any triangle add up to 180.
__________________________________________
Given Δ ACB, we are given:
_____________
m∡C= ?
m∡B = (4x + 5)
m∡A = 65
_____________________
So, given Δ ACB; m∡A + m∡B + m∡c = 180;
→Plug in our known values and rewrite:
___________________________________
Given Δ ACB; 65 + 4x + 5 + (m∡c) = 180;
→Simplify, and rewrite:
___________________________________
Given Δ ACB; 4x + 70 + (m∡c) = 180;
→Subtract "70" from each side of the equation; and rewrite:
___________________________________
Given Δ ACB; 4x + (m∡C) = 110;
→Subtract "4x" from EACH SIDE of the equation; to isolate: "(m∡c)" on one side of the equation; and "solve in terms of "(m∡C)" ;
______________________________________________
Given Δ ACB' m∡C = 110 - 4x ;
__________________________________________
So, we know that: (110 - 4x) + (9x - 5) = 180; (since all angles on a straight line add up to 180.
____________________
We can solve for "x".
____________________
(110 - 4x) + (9x - 5) = 180;
________________________
Rewrite as:
___________
(110 - 4x) + 1(9x - 5) = 180 ; (Note: there is an implied coefficient of "1"; since anything multiplied by "1" equals that same value).
_______________________
Note the "distributive property of multiplication":
_________________
a*(b+c) = ab + ac ; AND:
a*(b - c) = ab - ac .
_______________________
So, +1(9x - 5) = (+1*9x) - (+1*5) = 9x - 5 ;
__________________________
So we can rewrite:
___________________
(110 - 4x) + (9x - 5) = 180 ; as:
________________________
110 - 4x + 9x - 5 = 180 ; We can simplify this by combining "like terms" on the "left-hand side" of the equation:
_________________________________________________
110 - 5 = 105 ;
-4x + 9x = 5x;
______________
So, rewrite as: 5x + 105 = 180; Subtract "105" from EACH side; to get:
_____________________________________
5x = 75 ; Now, divide each side of the equation by "5";
to get: x = 15.
_____________________________________________
Now, we want to know: m∡BCD; which equals:
_____________________________________________
9x - 5 ; let us substitute "15" for "x"; and solve:
______________________
9x - 5 = 9*(15) - 5 = 135 - 5 = 130.
_____________________________
The answer: m∡BCD = 130°
________________________