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REY [17]
3 years ago
7

The local high school sold 1914 tickets this year to its spring musical. That was 174 more tickets sold than last year. What is

the percent increase in the number of tickets sold?
Mathematics
1 answer:
pantera1 [17]3 years ago
3 0

Answer:

.909 (ROUNDED)

Step-by-step explanation:

In order to do this all you need to do is divide the number with the number you got this year, 1914, and with the number last year.

1914-174=1740

1740 was the amount they got last year

Now you want to find the percent difference between the two.

1740/1914=.909090 (Repeats)

So the percent increase would be

.909090

.101010

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Identify the like terms in the list.
MrRa [10]

Answer:

17x and 3x

Step-by-step explanation:

like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power.

8 0
1 year ago
Y = 4x - 6
Studentka2010 [4]

Answer:

B) 2x - 12x - 18 = 8

Step-by-step explanation:

2x - 3y = 8

If y = 4x - 6, then substitute and solve:

2x - 3(4x - 6) = 8

2x - 12x - 18 = 8

10x - 18 = 8

10x = 8 + 18

10x = 26

x = 26/10

x = 2.6

y = 4(2.6) - 6

y = 10.4 - 6

y = 4.4

8 0
3 years ago
A,D,N, and X are collinear points. D is between N and A. NA+AX=NX. Draw a diagram that represents this information. Help!!!
GREYUIT [131]
I hope this helps you out!

3 0
3 years ago
Show that every triangle formed by the coordinate axes and a tangent line to y = 1/x ( for x > 0)
vfiekz [6]

Answer:

Step-by-step explanation:

given a point (x_0,y_0) the equation of a line with slope m that passes through the  given point is

y-y_0 = m(x-x_0) or equivalently

y = mx+(y_0-mx_0).

Recall that a line of the form y=mx+b, the y intercept is b and the x intercept is \frac{-b}{m}.

So, in our case, the y intercept is (y_0-mx_0) and the x  intercept is \frac{mx_0-y_0}{m}.

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph (x_0,\frac{1}{x_0}). Which means that y_0=\frac{1}{x_0}

The slope of the tangent line is given by the derivative of the function evaluated at x_0. Using the properties of derivatives, we get

y' = \frac{-1}{x^2}. So evaluated at x_0 we get m = \frac{-1}{x_0^2}

Replacing the values in our previous findings we get that the y intercept is

(y_0-mx_0) = (\frac{1}{x_0}-(\frac{-1}{x_0^2}x_0)) = \frac{2}{x_0}

The x intercept is

\frac{mx_0-y_0}{m} = \frac{\frac{-1}{x_0^2}x_0-\frac{1}{x_0}}{\frac{-1}{x_0^2}} = 2x_0

The triangle in consideration has height \frac{2}{x_0} and base 2x_0. So the area is

\frac{1}{2}\frac{2}{x_0}\cdot 2x_0=2

So regardless of the point we take on the graph, the area of the triangle is always 2.

6 0
3 years ago
Needs help with both
a_sh-v [17]

Answer:

flip it please

Step-by-step explanation:

d for 1 and a for 2

5 0
3 years ago
Read 2 more answers
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